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Viefleur [7K]
3 years ago
15

2+2 is what and also what is 56 divided by 8

Mathematics
2 answers:
guajiro [1.7K]3 years ago
8 0

Answer:

2+2 is 4 - 1 that's 3 quick mafs

and 56 ÷ 8 is 7

matrenka [14]3 years ago
6 0

Answer:1:4 2:7

Step-by-step explanation:

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Solve the linear differential equation 2xy' + y = 2√x
77julia77 [94]

Answer:

Step-by-step explanation:

General form of the linear differential equation can be written as:

\frac{dy}{dx}+P(x)y=Q(x)

For this case, we can rewrite the equation as:

\frac{dy}{dx}+\frac{1}{2x}y=\frac{\sqrt{x}}{x}

Here P(x) =\frac{1}{2x}; Q(x)=\frac{\sqrt{x}}{x}

To find the solution (y(x)), we can use the integration factor method:

Fy(x)=\int Q(x)Fdx+C \rightarrow F=e^{\int P(x)dx

Then F=e^{\int \frac{1}{2x}dx}=e^{\frac{1}{2}\ln|x|\right}=\sqrt{|x|}

So, we can find:

y\sqrt{|x|}=\int \frac{\sqrt{x}\sqrt{|x|}}{x}dx+C

Suppose that x\in \double R, then \sqrt{|x|}=\sqrt{x} , and we find:

y\sqrt{x}=x+C \rightarrow y(x)=\sqrt{x}+\frac{C\sqrt{x}}{x}

To check our solution is right or not, put your y(x) back to the ODE:

y' = \frac{1}{2\sqrt{x}}-\frac{C}{2\sqrt{x^{3}}}

2xy'=\frac{x-C}{\sqrt{x}}

2xy'+y=\frac{x-C}{\sqrt{x}}+\sqrt{x}+\frac{C\sqrt{x}}{x}=2\sqrt{x}

(it means your solution is right)

3 0
2 years ago
Match the graph with the correct equation
tatyana61 [14]
<h3>Answer: Choice D) </h3>

y + 2 = -(x - 4)

============================================

Explanation:

The slope of this line is -1 because each time we move down 2 units, we move to the right 2 units. So slope = rise/run = -2/2 = -1

The slope formula says the same thing more or less. Let's pick the two points (0,2) and (2,0) to find the slope through them

m = (y2-y1)/(x2 - x1)

m = (0-2)/(2-0)

m = -2/2

m = -1

-------------

Using that slope and a point on the line, we can form the equation. We can pick any point really as long as it's on the line. However, to have it match with the answer choices, we'll have to pick the point (4,-2)

Turn to point slope form

y - y1 = m(x - x1)

y - y1 = -1(x - x1) ... plug in the slope

y  - (-2) = -(x - 4) ... plug in the point (x1,y1) = (4, -2)

y + 2 = -(x - 4)

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x^2=225

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