(a) The integral is equal to the area of the triangle; it has height 20 and base 10, so the area is 20*10/2 = 100.
(b) The integral is equal to the area of the semicircle with radius 10. It's also under the horizontal axis, so the area is negative. The semicircle has area
, so the integral is -50π.
(c) First compute

which is the area of the triangle on the right. It has height and base 5, so its area is 25/2.
Then split up the desired integral as

and plug in the integral values you know:

I'm not 100% sure but I believe it's $250
Answer:
- cos (x) cos (2x) - 2sin(x) sin(2x)
Solution:
(See the solution in the photo)
Answer:
8.0623
Explanation:
Distance between two points = √
(
−
2 − − 9
)^
2
+
(
−
2 − − 6)^
2
= √
7
^2+
4
^2
=
√
49 + 16
=√
65 = 8.0623
Distance between points (-9, -6) and (-2, -2) is 8.0623