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3 years ago

Which of the following polar equations is a circle with its center at the pole and a radius of 3?

Mathematics

1 answer:

Bumek [7]3 years ago

6 0

Answer:

7.3

Step-by-step explanation:

I think

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Kristen invests $ 5745 in a bank. The bank 6.5% interest compounded monthly. How long must she leave the money in the bank for i

podryga [215]

Answer:

1. 10.7 years

2. 17.0 years

3. 2nd option

Step-by-step explanation:

Use formula for compounded interest

$A=P\cdot \left(1+\dfrac{r}{n}\right)^{nt},$

where

A is final value, P is initial value, r is interest rate (as decimal), n is number of periods and t is number of years.

In your case,

1. P=$5745, A=2P=$11490, n=12 (compounded monthly), r=0.065 (6.5%) and t is unknown. Then

$11490=5745\cdot \left(1+\dfrac{0.065}{12}\right)^{12t},\\ \\2=(1.0054)^{12t},\\ \\12t=\log_{1.0054}2,\\ \\t=\dfrac{1}{12}\log_ {1.0054}2\approx 10.7\ years.$

2. P=$5745, A=3P=$17235, n=12 (compounded monthly), r=0.065 (6.5%) and t is unknown. Then

$17235=5745\cdot \left(1+\dfrac{0.065}{12}\right)^{12t},$

$3=(1.0054)^{12t},$

$12t=\log_{1.0054}3,$

$t=\dfrac{1}{12}\log_{1.0054}3\approx 17.0\ years.$

3. <u>1 choice:</u> P=$5745, n=12 (compounded monthly), r=0.065 (6.5%), t=5 years and A is unknown. Then

$A=5745\cdot \left(1+\dfrac{0.065}{12}\right)^{12\cdot 5},\\ \\A=5745\cdot (1.0054)^{60}\approx \$7936.39.$

<u>2 choice:</u> P=$5745, n=4 (compounded monthly), r=0.0675 (6.75%), t=5 years and A is unknown. Then

$A=5745\cdot \left(1+\dfrac{0.0675}{4}\right)^{4\cdot 5},\\ \\A=5745\cdot (1.0169)^{20}\approx \$8032.58.$

The best will be 2nd option, because $8032.58>$7936.39

5 0

3 years ago

Read 2 more answers

Help ;-; me please;-;

Diano4ka-milaya [45]

Answer: 13 is c im pretty sure and 14 is a im think hope fully it helps

Step-by-step explanation:

8 0

3 years ago

BASED ON THE GRAPH, WHICH STATEMENT IS CORRECT?

abruzzese [7]

Answer:

i would go for a but im not really sure. sorry if incorrect

Step-by-step explanation:

3 0

3 years ago

The price of one share of stock in BadInvestment.com plunged 14 points in 4 weeks. Find the average change in stock price per da

mariarad [96]

$averge\ change=\frac{number\ of\ points}{number\ of\ days}\\\\
4week=28days\\\\
average\ change=\frac{14}{28}=0,5\frac{stock}{day}\\\\Solution\ is\ 0,5\frac{stock}{day}.$

7 0

3 years ago

What are the aptitude, period, and midline of the function?

tester [92]

The picture won’t show on mine?

6 0

3 years ago