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kondor19780726 [428]
3 years ago
7

PLEASE HELP, BRAINLIEST FOR THE BEST ANSWER

Mathematics
1 answer:
Zolol [24]3 years ago
5 0

Answer:

Use the distance formula to determine the distance between the two points.

Distance

=

√(x2−x1)^2 + (y2−y1)^2

Substitute the actual values of the points into the distance formula.

√ ( (−6) − 0)^2 +( (−3) − 4)^2

Subtract 0 from −6

√(−6)^2 + ( ( −3 ) −4 )^2

Raise −6 to the power of 2

√36 + ( ( −3 ) −4 )^2

Subtract 4 from −3

√36 + ( −7 )^2

Raise −7 to the power of 2

√ 36 + 49

Add 36 and 49

√85

You might be interested in
Clarissa works in sales for a software company. Her pay each month varies, because each month she receives a base pay of $2,400.
Natasha_Volkova [10]
If Clarissa had $18,000 in sales during the month of November, and she earns an 8% commission on the dollar value of her sales, then we first need to find out how much she made on commissions alone for the month of November. We can do that by multiplying the percentage by the amount of money she made off of sales.

To do this, we first must convert the percentage into a decimal. We can do this by either dividing the percent by 100, or (my personal shortcut) just shifting the decimal point over 2 places to the left.

8% = 0.08

Now, we multiply the decimal by the amount she made

0.08 * 18000 = 1440

So Clarissa made $1,440 off of commissions. But that's not what the question is asking. It wants to know what percentage of Clarissa's income for the month of November was from commissions. We can do this by adding her base pay to the amount she made from commissions, and then dividing the amount she got from commissions by the total amount she made for the month of November.

2400 + 1440 = 3840

1440 / 2840 = 0.375

We can convert this decimal back to a fraction by multiplying by 100

0.375 = 37.5%

37.5% of Clarissa's pay for the month of November was from commissions.
Hope that helped =)
5 0
3 years ago
What did I do wrong?! What’s the right answer?!
skad [1K]

Answer:

The mistake was on your second step where you took b to be +6, yet it has to be -6.

8 0
4 years ago
.Un recipiente cilíndrico de 5cm de radio y 10cm de altura se llena de agua. Si la masa del recipiente lleno es de 2kg, ¿cuál es
Lera25 [3.4K]

Answer:

La masa del recipiente vacío es 1,2146 kg.

Step-by-step explanation:

La densidad se define como la propiedad que tiene la materia, ya sean sólidos, líquidos o gases, para comprimirse en un espacio determinado. En otras palabras, la densidad es una magnitud que permite medir la cantidad de masa que hay en determinado volumen de una sustancia. Entonces, la expresión para el cálculo de la densidad es el cociente entre la masa de un cuerpo y el volumen que ocupa:

densidad= \frac{masa}{volumen}

Entonces la masa puede ser expresada como:

masa= densidad*volumen

En este caso:

  • densidad del agua= 1000 \frac{kg}{m^{3} }
  • volumen del recipiente cilíndrico= π*radio²*altura= π*(5 cm)²* 10 cm= π*(0,05 m)²*0,1 m= 7,854*10⁻⁴ m³

Reemplazando:

masa= 1000 \frac{kg}{m^{3} } * 7,854*10⁻⁴ m³

masa=0.7854 kg

Si la masa del recipiente lleno es de 2 kg, entonces se le resta la masa de agua calculada:

2 kg - 0,7854 kg= 1,2146 kg

Entonces,<u><em> la masa del recipiente vacío es 1,2146 kg.</em></u>

<u><em> </em></u>

<u><em></em></u>

8 0
3 years ago
Someone helppp pls due in 5 min <br> I will thank
patriot [66]
Angel 3 is adjacent to Angel 4 therefore they are equal.
5 0
3 years ago
Suma a 3 numere naturale este 163. Scazand al treilea numar din suma primelor doua numere, obtinem 67. Scazand primul numar din
Vika [28.1K]

Answer: x=63, y=52, z=48

Step-by-step explanation:

The complete question in english is:

The sum of 3 natural numbers is 163. By subtracting the third number from the sum of the first two numbers, we get 67. By subtracting the first number from the sum of the last 2 numbers, we get 37. Determine the 3 numbers

According to this we have a system with three equations and three unknown values:

x+y+z=163 (1)

x+y-z=67 (2)

-x+y+z=37 (3)

Let's begin by isolating x from (1):

x=163-y-z (4)

And substitute (4) in (2):

163-y-z+y-z=67 (5)

Isolating z:

z=48 (6) We have found the first number

Substituting (6) in (1):

x+y+48=163 (7)

Adding (7) to (3):

\left \{ {{x+y+48=163} \atop {-x+y+z=37}} \right

We have the following:

2y+96=200

Isolating y:

y=52 (8) This is the second number

Substituting (6) and (8) in (1):

x+52+48=163 (9)

Isolating x:

x=63 (10) This is the third number

8 0
4 years ago
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