Answer:
2) 1) 25
2) 30
Step-by-step explanation:
2) 1) 650 - 400 = 250
250 / 10 = 25
2) 850 - 400 = 450
450 / 15 = 30
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<span>Instead of k, k+1, k+2, you should use k, k+2, k+4 with the constraint that k is even (i.e. if you return an odd integer for k, or a non-integer, then return no solution).
</span><span>k + (k+2) + (k+4) = 4k
</span><span>3k + 6 = 4k
k = 6
</span><span>Indeed, 6+8+10 = 4*6.</span>
You're looking for 3), a meter.
Answer:
Step-by-step explanation:
get the x alone by subtracting 3 from each side.
3x+3-3<36-3
3x<33
divide by three
3x/3<33/3
x<11
The subsets of {b, d} are {}, {b}, {d}, {b, d}. Thus the subsets of interest to you are
... {a, e}, {a, b, e}, {a, d, e}, {a, b, d, e}
_____
We know your final sets will include {a, e}, so they're not part of the variable portion of the subsets. We know c is not included, so we can leave it out of consideration. That leaves only b and d included (or not) in the variable portion of the sets of interest. We only needed to find all the ways that we could have b or d or neither or both, that is, the subsets of {b, d}. Then we form the union of each of those subsets with {a, e}.