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Ira Lisetskai [31]
3 years ago
15

What is the x-value in the solution to this system of linear equations?

Mathematics
1 answer:
Hoochie [10]3 years ago
5 0

Answer:

anwer is 4 i m not sure

of i m right plz give me the brainliest

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Find the values of x and y if
soldi70 [24.7K]

Answer:

see explanation

Step-by-step explanation:

Since the triangles are congruent then corresponding sides are congruent, then

CA = NE , that is

4x + 3 = 11 ( subtract 3 from both sides )

4x = 8 ( divide both sides by 4 )

x = 2

----------------------------------------

AR = EW, that is

4y - 12 = 10 ( add 12 to both sides )

4y = 22 ( divide both sides by 4 )

y = 5.5

-------------------------------------------

NW = x + y = 2 + 5.5 = 7.5

CR = NW = 7.5

5 0
3 years ago
Can somebody please help me?
victus00 [196]

Answer:

D

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP!!!!!!!!
steposvetlana [31]

Answer:

4.6.

Step-by-step explanation:

The rocket hits the ground when h(t) = 0. So

-16t^{2} + 72t + 7 = 0

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this question:

-16t^{2} + 72t + 7 = 0

So

a = -16, b = 72, c = 7

Then

\bigtriangleup = 72^{2} - 4*(-16)*7 = 5632

t_{1} = \frac{-72 + \sqrt{5632}}{2*(-16)} = -0.1

t_{2} = \frac{-72 - \sqrt{5632}}{2*(-16)} = 4.6

Time is a positive measure, so the answer is 4.6.

6 0
3 years ago
Find the angle between u=(8, -2) and v=(9,3) Round to the nearest tenth of a degree.
Kryger [21]

Answer:

the angle between u=(8, -2) and v=(9,3) is 32.5°

Step-by-step explanation:

u=(8,-2)=(u1,u2)→u1=8, u2=-2

v=(9,3)=(v1,v2)→v1=9, v2=3

We can find the angle between two vectors using the formula of dot product:

u . v =║u║║v║cos α   (1)

And the dot product is:

u . v = u1 v1 + u2 v2

u . v = (8)(9)+(-2)(3)

u . v = 72-6

u . v = 66


║u║=√(u1²+u2²)

║u║=√((8)²+(-2)²)

║u║=√(64+4)

║u║=√(68)

║u║=√((4)(17))

║u║=√(4)√(17)

║u║=2√(17)


║v║=√(v1²+v2²)

║v║=√((9)²+(3)²)

║v║=√(81+9)

║v║=√(90)

║v║=√((9)(10))

║v║=√(9)√(10)

║v║=3√(10)


Replacing the known values in the formula of dot product (1):

u . v =║u║║v║cos α

66 = 2√(17) 3√(10) cos α

Multiplying:

66 = 6√((17)(10)) cos α

66 = 6√(170) cos α

Solving first for cos α: Dividing both sides of the equation by 6√(170):

\frac{66}{6\sqrt{170} }=\frac{6\sqrt{170}cos \alpha}{6\sqrt{170} }

\frac{66}{6\sqrt{170}}=cos\alpha

Simplifying: Dividing the numerator and denominator on the left side of the equation by 6:

(66/6)/(6√170/6)=cosα→11/√170=cosα→cosα=11/√170

cosα=11/13.03840481→cosα=0.84366149

\alpha=cos^{-1}0.84366149\\\alpha=32.47119205^{\°}\\ \alpha=32.5^{\°}

5 0
4 years ago
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Any amount $30 or over.
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3 years ago
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