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satela [25.4K]
3 years ago
12

A changes

Mathematics
2 answers:
kupik [55]3 years ago
8 0

Answer: 8/11

Step-by-step explanation:

This is because there are a total of 22 bulbs. 16 of those bulbs work, giving us the fraction: 16/22. If you simplify 16/22 by dividing the numerator and denominator by 2, you get 8/11.

pantera1 [17]3 years ago
8 0
<h3>Answer:  Choice C)  40/77</h3>

=================================================

Explanation:

There are 16 working bulbs out of 6+16 = 22 bulbs total.

The probability of randomly selecting a working bulb is 16/22

After that first bulb is selected and not put back, the probability of randomly selecting another working bulb is 15/21. Take note that I subtracted 1 from each part of the original fraction.

So we get the answer of

(16/22)*(15/21) = 240/462 = 40/77 which is choice C.

------------

Extra info:

  • Choice A is only true if Ken puts the first selection back. You would compute (16/22)*(16/22) = 64/121. However, it sounds like he's not doing replacement. So whatever is selected is not put back. This is why I ruled out choice A.
  • Choice B is ruled out as well because 16/22 = 8/11 refers to the probability of one working bulb (instead of 2 in a row)
  • It's not clear how the fraction of choice D is formed, but we can rule it out because choice C is the answer.
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3 years ago
If an M:N relationship is mandatory on both sides, and if both relations resulting from the entities involved in the relationshi
aalyn [17]

Answer:

3

Step-by-step explanation:

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I hope you find this information useful and interetsing! Good luck!

4 0
3 years ago
Chaney deposits $1435.73 into a savings account that pays a simple annual interest rate of 1.32%. How much interest will she ear
Aneli [31]

Answer:

Interest Chaney earns after 3 years is  $56.85

Step-by-step explanation:

Given:

Amount deposited = $1435.73

Simple annual interest rate = 1.32% = 1.32/ 100 = 0.0132

To find: Interest after 3 years

We know that the formula to calculate the interest amount is

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where,

P is the initial amount deposited

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