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solong [7]
3 years ago
15

Two vertical posts stand side by side. One post is 8 feet tall andtheother is 17 feet tall. If a 24-foot wire is stretched betwe

en the tops of the posts, how far apart are theposts?
Mathematics
1 answer:
allsm [11]3 years ago
3 0

Answer:

Post Brackets Post Brackets Post Bases Post Cap Connectors Simpson Strong-Tie in Post Cap Connectors Wood to Concrete Nominal Post Size (in.): 4x4 in Post Bases Nominal Post Size (in.): 6x6 in Post Bases 176Results Sort by:Top Sellers Top SellersMost PopularPrice Low to HighPrice High to LowTop Rated Products Get It Fast In Stock at Store Today

Step-by-step explanation:

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Find the equations of a line through these 2 points
stiv31 [10]

answer is 2.2 66 88862 u88272

4 0
2 years ago
I feel like this is the same thing from my last question (about how to find arc and angle lengths) but it looks very different.
Gnesinka [82]

Yes it is the same except there are two arcs you need to find the length for in this one.

7 0
3 years ago
Select the correct answer. 3 A linear function has a y-intercept of -12 and a slope of 3/2. What is the equation of the line?
emmasim [6.3K]

Answer:

a. y = 3/2x - 12

Step-by-step explanation:

Slope is y = mx + b

Slope or m = 3/2

y-intercept or b = -12

Substitute m for 3/2 and b for -12 then the answer would be y = 3/2x - 12

8 0
2 years ago
If 3x + 11 = 4x - 5, what is x?
Andrew [12]

Answer:

16v

Step-by-step explanation:

3x + 11 = 4x - 5

11+5 = 4x -3x

x = 16

I hope im right!!

4 0
2 years ago
Read 2 more answers
Please I need the polynomial for this problem, if you don’t know then don’t answer! Wrong answers will be reported
babymother [125]

Answer:

Area = (36π - 12πx + x²π) mm²

Step-by-step explanation:

Given that,

radius of lense = 6mm

Length from outer layer of pupil to lense = x mm

Radius of pupil = 6 - x mm

<h3>Formula to calculate area of pupil</h3><h3> Area = π r²</h3>

<em> where r is radius of pupil</em>

Area = π (6 -x)²

Area = π (6² -2(6)(x) + x²)

Area = π (36 -12x +x²)

Area = (36π - 12πx + x²π) mm²

So, the polynomial in standard form that represent the area of pupil in terms of π =  (36π - 12πx + x²π) mm²

5 0
3 years ago
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