HELP PLEASE !!!!
2 answers:
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Answer:
Step-by-step explanation:
Grouping the like terms.
Combining the like terms.
Hello,
if the question is to solve the equation:
1) log must exist:
a)==>2r²-27>0==>(r-√(27/2))(r+√(27/2))==> outside the roots
r<-√(27/2) or r>√(27/2)
b)==>3r²+12r>0 ==>3r(r+4)>0 ==>outside the roots
r>0 or r<-4
==>r<-4 or r>√(27/2)=3.6742...
If this is realized:
2r-27=3r²+12r
==>r²+12r+27=0
Δ=12²-4*27=36=6²
r=(-12+6)/2=-3 or r=(-12-6)/2=-9
One solution r=-9
Proof
if the question is to solve the equation:
1) log must exist:
a)==>2r²-27>0==>(r-√(27/2))(r+√(27/2))==> outside the roots
r<-√(27/2) or r>√(27/2)
b)==>3r²+12r>0 ==>3r(r+4)>0 ==>outside the roots
r>0 or r<-4
==>r<-4 or r>√(27/2)=3.6742...
If this is realized:
2r-27=3r²+12r
==>r²+12r+27=0
Δ=12²-4*27=36=6²
r=(-12+6)/2=-3 or r=(-12-6)/2=-9
One solution r=-9
Proof
Based on the calculations, the slowest rate is equal to 4 gallons per minute.
<u>Given the following data:</u>
- Distance from shore = 12 km.
- In-rate = 3 gallons per minute.
- Rowing rate = 24 km per hour.
Let's assume the boat would sink if it takes in more than 20 gallons of water.
<u>Conversion:</u>
- 24 km/h to km/min =
= 0.4 km/min.
Translating the word problem into an algebraic expression, we have;
Therefore, the slowest rate is equal to 4 gallons per minute.
Read more on distance here: brainly.com/question/10545161