That is close: you have the intercepts correct and the discontinuous point at x=-1 and x=3. The only thing is that you need to fix is the y values of the discontinuous points.
Without any coefficients, your graph is basically y=1, and you need it to resemble y=-5 to get the right y values. Normally, that just involves multiplication by -5 so multiply your function by -5 and you should get a correct graph.
And make sure to denote it with y= since it is an equation
![\frac{8- \sqrt[]{_2(-8+x)} }{2} ,](https://tex.z-dn.net/?f=%20%5Cfrac%7B8-%20%5Csqrt%5B%5D%7B_2%28-8%2Bx%29%7D%20%7D%7B2%7D%20%2C)
