How many solutions exist if 36x^2 + 96x + 75 = 0?
1 answer:
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Answer:
Last option; x < 2 and x > -1
Step-by-step explanation:
1. We know 2x − 1 < 3 and 2x − 1 > −3, so let's solve both of these inequalities.
2. (Solving for 1st condition)
Step 1: Add 1 to both sides.
Step 2: Divide both sides by 2.
3. (Solving for 2nd condition)
Step 1: Add 1 to both sides.
Step 2: Divide both sides by 2.
4. Now, we know that the value of x is greater than -1 but less than 2, and we can represent it on a number line like this:
