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Strike441 [17]
3 years ago
10

How many solutions exist if 36x^2 + 96x + 75 = 0?

Mathematics
1 answer:
Gelneren [198K]3 years ago
8 0

Answer:

3(12x² + 32x +25)

hope it helps :)

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Last option; x < 2 and x > -1

Step-by-step explanation:

1. We know 2x − 1 < 3 and 2x − 1 > −3, so let's solve both of these inequalities.

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Step 1: Add 1 to both sides.

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Step 2: Divide both sides by 2.

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3. (Solving for 2nd condition)

Step 1: Add 1 to both sides.

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Step 2: Divide both sides by 2.

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4. Now, we know that the value of x is greater than -1 but less than 2, and we can represent it on a number line like this:

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