Question

PLEASE ANSWER QUICK!!! 30 POINTS

Answer 1

Answer is 150°. Work is attached

Answer 2

Answer:

Solution given;

<ABD=<BAC+<ACB

Since exterior angle of a triangle is equal to the sum of two opposite interior angle

26x+20=19x-15+9x+25

solve like terms

26x+20=28x+10

subtracting both by 10

26x+20-10=28x+10-10

Subtracting both side by 26x

10=28x-26x

2x=10

dividing both side by 2

2x/2=10/2

x=5

Now

<ABD=26*5+20=l50°

The value of <ABD is 150°