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SCORPION-xisa [38]
3 years ago
15

PLEASE ANSWER QUICK!!! 30 POINTS

Mathematics
2 answers:
Aleksandr [31]3 years ago
7 0
Answer is 150°. Work is attached

shusha [124]3 years ago
4 0

Answer:

Solution given;

<ABD=<BAC+<ACB

<u>Since</u><u> </u><u>exterior</u><u> </u><u>angle</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>triangle</u><u> </u><u>is</u><u> </u><u>equal</u><u> </u><u>to</u><u> </u><u>the</u><u> </u><u>sum</u><u> </u><u>of</u><u> </u><u>two</u><u> </u><u>opposite</u><u> </u><u>interior</u><u> </u><u>angle</u>

26x+20=19x-15+9x+25

solve like terms

26x+20=28x+10

subtracting both by 10

26x+20-10=28x+10-10

Subtracting both side by 26x

10=28x-26x

2x=10

dividing both side by 2

2x/2=10/2

x=5

Now

<ABD=26*5+20=l50°

<u>T</u><u>h</u><u>e</u><u> </u><u>v</u><u>a</u><u>l</u><u>u</u><u>e</u><u> </u><u>o</u><u>f</u><u> </u><u><</u><u>A</u><u>B</u><u>D</u><u> </u><u>i</u><u>s</u><u> </u><u>1</u><u>5</u><u>0</u><u>°</u>

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