The y-coordinate of the midpoint, M of the segment AB described by; A(-3,3) and B(5,7) is; 5.
<h3>What is the y-coordinate of the point M which is the midpoint of AB, defined by;
A(-3,3) and
B(5,7).</h3>
It follows from the task content that the y-coordinate of the midpoint, M of AB defined by; A(-3,3) and B(5,7) is to be determined.
Hence, it follows from coordinate geometry that the y-coordinate of the midpoint is such that;
y = (y(1) +y(2))/2
y = (3 + 7)/2
y = 5.
Ultimately, the y-coordinate of the midpoint of AB; A(-3,3) and B(5,7) is; y =5.
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Two lines to be parallel their slopes have to be equal.
so m1 = m = 4
y = mx + b ( Slope intercept form)
y = 4x + b
(3,0) is on the line:
0 = 12 + b
b = -12
y = 4x - 12
Answer:
2 1/4 cubic units is the answer
See attachment for the graph of the function f(x) = cos(x) - 3
<h3>How to graph the function?</h3>
The equation of the cosine function is given as:
f(x) = cos(x) - 3
The above function is a cosine function, and the parent function of the cosine function is
f(x) = cos(x)
This means that the function f(x) = cos(x) is translated 3 units down to get the function f(x) = cos(x) -3
Next, we plot the graph of the function f(x) = cos(x) - 3
See attachment for the graph of the function f(x) = cos(x) - 3
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The sum of the three interior angles would be 180°
Hope this helped
