Why was Sherman angry at the beginning of the text?

Based on their actions in A century ride, which inference about Lizzie and Maude as woman of the late 1800s is most valid?

pashok25 [27]

Answer:

idkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkk

Explanation:

3 0

3 years ago

a student combined 45.3 ml of a 0.549 m calcium nitrate ca(no₃)₂ solution with 75.05 ml of a 1.321 m ca(no₃)₂ solution. calculat

Maksim231197 [3]

The concentration of the final solution of Ca(NO₃)₂ made by combining 45.3 mL of a 0.549 M Ca(NO₃)₂ solution with 75.05 mL of a 1.321 M Ca(NO₃)₂ solution is 1.03 M

We'll begin by calculating the number of mole of Ca(NO₃)₂ in each solution. This can be obtained as follow:

<h3>For solution 1:</h3>

Volume = 45.3 mL = 45.3 / 1000 = 0.0453 L

Molarity = 0.549 M

Mole = Molarity x Volume

Mole of Ca(NO₃)₂ = 0.549 × 0.0453

<h3>For solution 2:</h3>

Volume = 75.05 mL = 75.05 / 1000 = 0.07505 L

Molarity = 1.321 M

Mole = Molarity x Volume

Mole of Ca(NO₃)₂ = 1.321 × 0.07505

Next, we shall determine the total mole of Ca(NO₃)₂ in the final solution. This can be obtained as follow:

Mole of Ca(NO₃)₂ in solution 1 = 0.0249 mole

Mole of Ca(NO₃)₂ in solution 2 = 0.0991 mole

Total mole = 0.0249 + 0.0991

<h3>Total mole = 0.124 mole</h3>

Next, we shall determine the total volume of the final solution.

Volume of solution 1 = 0.0453 L

Volume of solution 2 = 0.07505 L

Total Volume = 0.0453 + 0.07505

<h3>Total Volume = 0.12035 L</h3>

Finally, we shall determine the concentration of the final solution. This can be obtained as follow:

Total Volume = 0.12035 L

Total mole = 0.124 mole

<h3>Concentration =?</h3>

Concentration = mole / Volume

Concentration = 0.124 / 0.12035

<h3>Concentration = 1.03 M</h3>

Therefore, the concentration of the final solution of Ca(NO₃)₂ is 1.03 M

Learn more: brainly.com/question/25469095

5 0

3 years ago

The ranas copied the divide and rule policy of east india company was it true.

Valentin [98]

Answer:

they what to rule the country

5 0

3 years ago

A study suggests that about 80\%80%80, percent of undergraduate students are working at a job. Researchers plan to do a follow-u

Leni [432]

Using the z-distribution, it is found that the smallest sample size required to obtain the desired margin of error is of 4330.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which:

$\pi$ is the sample proportion.

z is the critical value.

n is the sample size.

The margin of error is given by:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

In this problem:

The estimate of the proportion is of $\pi = 0.8$ .

The desired margin of error is of M = 0.01.

90% confidence level, hence $\alpha = 0.9$ , z is the value of Z that has a p-value of $\frac{1+0.9}{2} = 0.95$ , so $z = 1.645$ .

Then, we solve for n to find the minimum sample size.

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.01 = 1.645\sqrt{\frac{0.8(0.2)}{n}}$

$0.01\sqrt{n} = 1.645\sqrt{0.8(0.2)}$

$\sqrt{n} = \frac{1.645\sqrt{0.8(0.2)}}{0.01}$

$(\sqrt{n})^2 = \left(\frac{1.645\sqrt{0.8(0.2)}}{0.01}\right)^2$

$n = 4329.6$

Rounding up, the smallest sample size required to obtain the desired margin of error is of 4330.

To learn more about the z-distribution, you can take a look at brainly.com/question/12517818

7 0

2 years ago

How do i deleted my account ASAP please 30 points

aksik [14]

$\huge{\underline{\underline{\mathfrak{\red{Answer}}}}}$

First login to your account in website of brainly
Go to edit profile
Then select the option of preferences
Then click delete my account.

7 0

3 years ago