Using the probability and odds concepts, it is found that the odds against it containing a number greater than or equal to 7 is
.
- A probability is the <u>number of desired outcomes divided by the number of total outcomes</u>.
- An odd is the <u>number of desired outcomes divided by the number of non-desired outcomes</u>.
In the rack, there are 15 balls, numbered from 1 to 15. Of those, <u>6 are less than 7</u>(against it containing a number greater than or equal to 7 is equivalent to it containing a number less than 7), thus:
- There are 6 desired outcomes.
- There are 9 non-desired outcomes.
The odd is:
![\frac{6}{9} = \frac{2}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B6%7D%7B9%7D%20%3D%20%5Cfrac%7B2%7D%7B3%7D)
The odds against it containing a number greater than or equal to 7 is
.
A similar problem is given at brainly.com/question/21094006
Answer: 13.71
Step-by-step explanation:
20+6+17+10+19+15+9=96
96/7=13.71
Answer:
i think its the vertex
Step-by-step explanation:
Answer:142
Step-by-step explanation: