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Dima020 [189]
3 years ago
9

Of the following fractions: 9/19, 5/11, 7/15, and 11/23, which is the largest?

Mathematics
2 answers:
solmaris [256]3 years ago
8 0

Answer:

silly question...I used technology to "cheat"

it is 11/23

<u>34155</u> <u>32775</u> <u>33649</u> <u>34485</u>

72105 72105 72105 72105

Step-by-step explanation:

ElenaW [278]3 years ago
8 0
11/23 is considered the largest.
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Step-by-step explanation:

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What is the perimeter of triangle ABC? Round each step to the nearest tenth. Please help me
Ad libitum [116K]

I would use the pythagorean theorem to find the lengths of each side. a² + b² = c².

Side AB is one we're looking for. If you make other right triangle with that same side you can see that one length is 4 and the other is 3. So, 4² + 3² = c² → 25 = c² → 5 = c. Side AB is length 5.

Side AC is another. Do the same with that side and you get that one length is 4 and the other is 3. (This is the same one as above) so side AC is length 5.

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8 0
4 years ago
Solve for the equation for the interval [0, 2pi). sec x/2 = cos x/2
Alenkinab [10]
Sec(x/2) = 1/cos(x/2)

sec(x/2)=cos(x/2) ----> cos^2(x/2)=1 ---> cos(x/2) = -1 and cos(x/2) = 1

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cos(x/2)=-1 ----> x/2 = pi -> x = 2pi. But the statement says [0,2pi), so 2pi can not be chosen.

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3 0
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Answer:

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Step-by-step explanation:

You will start by using the factor tree.

490

^

2 245

^

5 49

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7 7

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3 years ago
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