Answer:
<u>tulips bulbs cost $5; and daffodil bulbs costs $8 </u>
Step-by-step explanation:
Variables can be used to create equations and set up a system of equations. I used the following variables:
Tulip bulbs= t
Daffodil bulbs= d
We need create two equations using the total sales, and amount of each item sold. Using the variables I chose I set up an equation representing the sales of each girl.
Sumalee sold 6 tulip bulbs and 6 daffodil bulbs for $78.
6t+ 6d= 78
Jennifer sold 6 tulip bulbs and 4 daffodil bulbs for $62.
6t+ 4d= 62
Using the equations we can set up a system of equations. To solve the system you can use either the substitution method or the elimination method.
(substitution)
Isolate one of the variables in the first equation.
6t+ 6d-6t = 78-6t
6d/ 6= (-6t+78)/6
d= -t+13
Substitute d= -t+13 into equation 2 replacing variable d. Using the order of operations solve for t.
6t+ 4(-t+13) = 62
6t- 4t+52 = 62
2t = 10
<u>t= 5</u>
Substituting t=5 for the value of t in equation 1, and solve of d.
6(5)+ 6d= 78
30+ 6d= 78
6d=48
<u>d=8</u>
<u>This means one package of tulips bulbs cost $5, and one bag of daffodil bulbs costs $8 </u>
Answer:
a. 1965
b. 8 years
Step-by-step explanation:
For answers to questions like these it can work to consider the smallest possible dataset.
<h3>Dataset</h3>
For our purpose, consider the 9 years/values to be averaged to be ...
1, 2, 3, 4, 5, 6, 7, 8 ,9
<h3>Observations</h3>
a. The center value of the data set is 5. Its number is 5-1=4 more than the first one.
The first centered value is from the year 1961 +4 = 1965.
b. The 4 values at the beginning, and the 4 values at the end do not have a corresponding "average" value. That is, 4+4 = 8 values in the series are lost with respect to the number of average values.
8 years of values are lost.
11% = 11/100
2/9 + 11/100 + 1/10 = 389/900
389/900 x 350 = 151.3
350 - 151.3 = 198.7
Answer:
The slope of the line that passes through the points is 0 slope. That is B is the answer.
Can you show us the question?
