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3 years ago

What are the five Technology Drivers of Infrastructure Evolution

Computers and Technology

1 answer:

kakasveta [241]3 years ago

3 0

Answer:

The five eras are automated special-purpose machines, general-purpose mainframe and minicomputer computing, personal computers, client/server networks, and enterprise and Internet computing. Illustrated here are the typical computing configurations characterizing each of the five eras of IT infrastructure evolution.

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What do work places allow a company to do

anygoal [31]

D. They provide a platform for collaboration

8 0

3 years ago

Consider the following high-level recursive procedure: long long int flong long int n, long long int k long long int b b k+2; if

Stolb23 [73]

Answer:

f(long long, long long):

push rbp

mov rbp, rsp

push rbx

sub rsp, 40

mov QWORD PTR [rbp-40], rdi

mov QWORD PTR [rbp-48], rsi

mov rax, QWORD PTR [rbp-48]

add rax, 2

mov QWORD PTR [rbp-24], rax

cmp QWORD PTR [rbp-40], 0

jne .L2

mov QWORD PTR [rbp-24], 8

jmp .L3

.L2:

mov rax, QWORD PTR [rbp-40]

lea rdx, [0+rax*4]

mov rax, QWORD PTR [rbp-24]

lea rbx, [rdx+rax]

mov rax, QWORD PTR [rbp-48]

lea rdx, [rax+1]

mov rax, QWORD PTR [rbp-40]

sub rax, 1

mov rsi, rdx

mov rdi, rax

call f(long long, long long)

add rax, rbx

mov QWORD PTR [rbp-24], rax

.L3:

mov rdx, QWORD PTR [rbp-24]

mov rax, QWORD PTR [rbp-48]

add rax, rdx

add rsp, 40

pop rbx

pop rbp

ret

Explanation:

8 0

3 years ago

In Python please.

SOVA2 [1]

Answer:

negatives = []

zeros = []

positives = []

while True:

number = input("Enter a number: ")

if number == "":

break

else:

number = int(number)

if number < 0:

negatives.append(number)

elif number == 0:

zeros.append(number)

else:

positives.append(number)

for n in negatives:

print(n)

for z in zeros:

print(z)

for p in positives:

print(p)

Explanation:

Initialize three lists to hold the numbers

Create a while loop that iterates until the user enters a blank line

Inside the loop:

If the number is smaller than 0, put it in the negatives list

If the number is 0, put it in the zeros list

Otherwise, put the number in the negatives list

When the while loop is done, create three for loops to print the numbers inside the lists

5 0

3 years ago

Creating a map of your current knowledge is called __________.

poizon [28]

Answer:

D - Concept-mapping

Explanation:

3 0

3 years ago

a password to a certain database consists of digits that cannot be repeated. if the password is known to consist of at least 8 d

BaLLatris [955]

Answer:

$\frac{10!}{2}mins$

Explanation:

12 seconds to try one combination will be equivalent to $\frac{1}{12}\times 60 = \frac{1}{5} \ mins$

Password contain at least 8 digit i.e. password can contain 8, 9, 10 digit.

Password cannot contain more than 10 digit because it will give room for repetition which it is clearly stated that digit cannot be repeated.

Possible digit that can be used: 9,8,7,6,5,4,3,2,1,0.

Total number of passwords combination possible for each position in 8 digit.

1st position = 10, 2nd position = 9, 3rd position = 8, 4th position = 7, 5th position = 6, 6th position = 5, 7th position = 4, 8th position = 3. Total number of passwords combination possible in 8 digit is equivalent to $\frac{10!}{2}$ .

Total number of passwords combination possible for each position in 9 digit.

1st position = 10, 2nd position = 9, 3rd position = 8, 4th position = 7, 5th position = 6, 6th position = 5, 7th position = 4, 8th position = 3, 9th position = 2. Total number of passwords combination possible in 9 digit is equivalent to $\frac{10!}{1}$ .

Total number of passwords combination possible for each position in 10 digit.

1st position = 10, 2nd position = 9, 3rd position = 8, 4th position = 7, 5th position = 6, 6th position = 5, 7th position = 4, 8th position = 3, 9th position = 2, 10th position = 1. Total number of passwords combination possible in 10 digit is equivalent to 10!.

Adding them up and multiplying by $\frac{1}{5} \ mins$ to get the total number of time needed to guarantee access to database = $[\frac{10!}{2}\times\ \frac{10!}{1} \times 10!] \frac{1}{5}\ mins = \frac{10!}{2}$

7 0

3 years ago