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Makovka662 [10]

2 years ago

11

A stick is 5 m long. A rope is 12 times as long as the stick. If the rope is divided into 3 pieces, how many meters long is each

piece of rope?

2 answers:

alisha [4.7K]2 years ago

4 0

Answer:

20 meters

Step-by-step explanation:

12*5/3 is 20

Hope this helps plz hit the crown :D

kirill115 [55]2 years ago

3 0

Length of the rope = 12 x 5 = 60 m

Length of each divided rope = 60 divided by 3 = 20 m

Therefore, each piece of rope is 20 m long.

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liberstina [14]

4/6
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Oil is pumped continuously from a well at a rate proportional to the amount of oil left in the well. Initially there were millio

JulijaS [17]

Answer:

The amount of oil was decreasing at 69300 barrels, yearly

Step-by-step explanation:

Given

$Initial =1\ million$

$6\ years\ later = 500,000$

Required

At what rate did oil decrease when 600000 barrels remain

To do this, we make use of the following notations

t = Time

A = Amount left in the well

So:

$\frac{dA}{dt} = kA$

Where k represents the constant of proportionality

$\frac{dA}{dt} = kA$

Multiply both sides by dt/A

$\frac{dA}{dt} * \frac{dt}{A} = kA * \frac{dt}{A}$

$\frac{dA}{A} = k\ dt$

Integrate both sides

$\int\ {\frac{dA}{A} = \int\ {k\ dt}$

$ln\ A = kt + lnC$

Make A, the subject

$A = Ce^{kt}$

$t = 0\ when\ A =1\ million$ i.e. At initial

So, we have:

$A = Ce^{kt}$

$1000000 = Ce^{k*0}$

$1000000 = Ce^{0}$

$1000000 = C*1$

$1000000 = C$

$C =1000000$

Substitute $C =1000000$ in $A = Ce^{kt}$

$A = 1000000e^{kt}$

To solve for k;

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$t = 6\ A = 500000$

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$500000= 1000000e^{k*6}$

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$ln(0.5) = k*6$

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$k = \frac{-0.693}{6}$

$k = -0.1155$

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$\frac{dA}{dt} = kA$

Where

$\frac{dA}{dt}$ = Rate

So, when

$A = 600000$

The rate is:

$\frac{dA}{dt} = -0.1155 * 600000$

$\frac{dA}{dt} = -69300$

<em>Hence, the amount of oil was decreasing at 69300 barrels, yearly</em>

7 0

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Answer:

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