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WITCHER [35]
3 years ago
12

Joseph and Sanjay are trying to finish their math homework before their favorite TV show starts. Joseph finishes 2/3 of his prob

lems. Sanjay finishes 5 out of 7 of his problems. Who finishes a greater fraction of his problems in time?
Joseph or Sanjay?
Mathematics
1 answer:
kicyunya [14]3 years ago
5 0
The correct answer is Sanjay! :)

Explanation:
Joseph: 2/3
Sanjay: 5/7
2/3 and 5/7
14/21 and 15/21
Therefore, Sanjay is the answer.
You might be interested in
Which graph represents the solution to the system of inequalities below?
Reika [66]

Answer:

The correct option is;

B

Step-by-step explanation:

The given system of inequalities are;

5·x - 4·y > 4...(1)

x + y < 2...(2)

Representing both inequalities as a function of "y", gives;

For, 5·x - 4·y > 4...(1), we have;

-4·y > 4 - 5·x

y < 4/(-4) - 5·x/(-4)

∴ y < 5·x/4 - 1

For x + y < 2...(2), we have;

y < 2 - x

Therefore, y is less than the values given by the equation of the straight line equalities, and the feasible region is given by the common region under both dashed lines representing both inequalities as shown in the attached diagram created using Microsoft Excel

The correct option is therefore, B.

3 0
3 years ago
5th grade . pls help.
fiasKO [112]
4/16 and 1/4 happy to help :)
8 0
3 years ago
What is the size of the tv when it’s 66 inches long and 56 inches tall
aleksklad [387]
Area= 3696in squared
Perimeter= 244in
3 0
3 years ago
PLEASE HELP 99 POINTS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!111
SVETLANKA909090 [29]
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5 0
3 years ago
Read 2 more answers
A rectangle has a height of k2 + 3 and a width of k2 + 7.
ElenaW [278]

Answer:

The area of the rectangle in polynomial form is k^4 +10 k^2 + 21

Step-by-step explanation:

Given

Shape: Rectangle

Height: k^2 + 3

Width: k^2 + 7

Required

Area of the rectangle

The area of a rectangle is calculated as thus;

Area = Length * Width

By substituting k^2 + 3 for height and k^2 + 7 for width; This gives

Area = (k^2 + 3)(k^2 + 7)

Expand the bracket

Area = k^2(k^2 + 7) + 3(k^2 + 7)

Open each bracket

Area = k^2*k^2 + k^2*7 + 3*k^2 + 3*7

Area = k^4 +7 k^2 + 3k^2 + 21

Area = k^4 +10 k^2 + 21

Hence, the area of the rectangle in polynomial form is k^4 +10 k^2 + 21

5 0
3 years ago
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