Answer:
5, 8, 11 and 32
Step-by-step explanation:
For the first 3 terms, substitute n = 1, 2, 3 into the n th term formula
a₁ = 3(1) + 2 = 3 + 2 = 5
a₂ = 3(2) + 2 = 6 + 2 = 8
a₃ = 3(3) + 2 = 9 + 2 = 11
Similarly for tenth term, let n = 10
a₁₀ = 3(10) + 2 = 30 + 2 = 32
hope you can understand
6
I like to line up my addition problems vertically
2 1/5
+ 3 4/5
--------------
5 5/5
but 5/5 = 1
5 + 1
10:14
