3x-y=2....(i)
2x-y=3.....(ii)
now adding the eqn I and ii ,
3x-y=2
2x-y=3
+ + +
5x=5
x=1
Now substituting the value of x in eqn I
3×1-y=2
3-y=2
-y=-1
y=1
Each side of the square is 16 ft
The line perpendicular to x = 2 will be y = something. This line passes through (0,-4) so its equation is y = -4 (answer)
Answer:
We do not have the function g(x), but this can be solved in a trivial way.
The average rate of change in a interval is the slope over that interval, so the average rate of change of g(x) in the interval 1 < x < 5 is
p = (g(x2) - g(x1))/(x2 - x1) where x2 > x1
p = (g(5) - g(1))/(5 - 1) = (g(5) - g(1))/4
Now, suppose that i have the new equation h(x) = g(x) + x
the rate of change of this function, the average rate of change in the interval will be:
p' = (h(5) - h(1))/(5 - 1) = (g(5) + 5 - g(1) - 1)/4 = (g(5) - g(1))/4 + 4/4 = p +1
so p' > p
and the average rate of change of h(x) is bigger than the one of g(x) in the interval 1< x < 5
Answer:
62 is 90.5% of what number? 68.51 (I think)
