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Leto [7]
3 years ago
11

I WILL GIVE YOU BRAINLIEST! PLEASE HURRY IM TIMED.

Mathematics
1 answer:
Sergio [31]3 years ago
7 0
5.6 the answer is obviously
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Paul says that t = -3 is a reasonable solution to the inequality.
Lapatulllka [165]

Answer:

um the iniquality of what........................................

Step-by-step explanation:

i dont know i need points

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3 years ago
Nick and Adam work out together. Nick weighs 160 pounds and is gaining about 3 pounds per week. Adam weighs 195 pounds and is lo
Inessa [10]

Answer:

160+3x=195-2x

Needed 7 weeks

Step-by-step explanation:

Let x be the number of weeks.

<u>Nick</u>

  • weighs 160 pounds;
  • is gaining about 3 pounds per week;
  • gains 3x pounds in x weeks;
  • weighs 160 + 3x pounds after x weeks.

<u>Adam</u>

  • weighs 195 pounds;
  • is losing about 2 pounds per week;
  • loses 2x pounds in x weeks;
  • weighs 195 - 2x pounds in x weeks.

The equation that can be used to find the number of weeks that it will take them to weigh the same amount is

160+3x=195-2x

Solve this equation:

3x+2x=195-160\\ \\2x=35\\ \\x=7

6 0
3 years ago
PLZ HELP ME WITH THIS!!! I WILL MARK BRAINLIEST!!!
gladu [14]

Answer:

-2+2= 0

Step-by-step explanation:

he's incorrect bc 2 is greater than 0. so the sum is less than one of the numbers in the equation

6 0
3 years ago
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On a number line, what is the distance between -54 and 73?
AlladinOne [14]
The answer is d because when you go from positive to negative you add the positive number to get to zero and than add the number you are getting to make sense?

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3 years ago
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Write the equation for a line that has an initial value of 3 and 3/4 as it’s rate of change
frutty [35]

the slope goes by several names

• average rate of change

• rate of change

• deltaY over deltaX

• Δy over Δx

• rise over run

• gradient

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however, is the same cat wearing different costumes.

initial value of 3, namely when x = 0, y = 3, so we have the point (0 , 3) and it has a rate or slope of 3/4.

(\stackrel{x_1}{0}~,~\stackrel{y_1}{3})\qquad \qquad \stackrel{slope}{m}\implies \cfrac{3}{4} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{3}=\stackrel{m}{\cfrac{3}{4}}(x-\stackrel{x_1}{0})\implies y=\cfrac{3}{4}x+3

3 0
3 years ago
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