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Leto [7]
3 years ago
11

I WILL GIVE YOU BRAINLIEST! PLEASE HURRY IM TIMED.

Mathematics
1 answer:
Sergio [31]3 years ago
7 0
5.6 the answer is obviously
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The value of a car over a period of 8 years is linear.
STALIN [3.7K]

I guess A i don't know hope the answer is correct

7 0
3 years ago
High divers use the height of the diving platform to calculate the speed at which they enter the
madreJ [45]

a. 3h = -12 + 5s

b. Speed = 51. 6 miles per hour

c. Height = 76 feet

<h3>How to determine the value</h3>

Given the function;

5s - 3h = 12

Where;

  • s is the speed in miles per hour
  • h is the height in feet

a. To solve for 3h

We have;

- 3h = 12 - 5s

3h = -12 + 5s

b. If the height is 82 feet , then

5s - 3(82) = 12

5s - 246 = 12

collect like terms

5s = 12 + 246

5s = 258

Make 's' the subject

s = 258/ 5

s = 51. 6 miles per hour

c. If the speed is 48 miles per hour, we have;

5(48) - 3h = 12

240 - 3h = 12

collect like terms

-3h = 12 - 240

-3h = -228

Make 'h' the subject

h = -228/ -3

h = 76 feet

Thus, the speed and height are 51. 6 miles per hour and 76 feet respectively.

Learn more about speed here:

#SPJ1

4 0
2 years ago
Can someone please help me with this question?
vodka [1.7K]

Answer:

Answer is D hope this helps :)

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Please help with these partial fractions!!!
VARVARA [1.3K]

a. Factorize the denominator:

\dfrac{x+14}{x^2-2x-8}=\dfrac{x+14}{(x-4)(x+2)}

Then we're looking for a,b such that

\dfrac{x+14}{x^2-2x-8}=\dfrac a{x-4}+\dfrac b{x+2}

\implies x+14=a(x+2)+b(x-4)

If x=4, then 18=6a\implies a=3; if x=-2, then 12=-6b\implies b=-2. So we have

\dfrac{x+14}{x^2-2x-8}=\dfrac3{x-4}-\dfrac2{x+2}

as required.

b. Same setup as in (a):

\dfrac{-3x^2+5x+6}{x^3+x^2}=\dfrac{-3x^2+5x+6}{x^2(x+1)}

We want to find a,b,c such that

\dfrac{-3x^2+5x+6}{x^2(x+1)}=\dfrac ax+\dfrac b{x^2}+\dfrac c{x+1}

Quick aside: for the second term, since the denominator has degree 2, we should be looking for another constant b' such that the numerator of the second term is b'x+b. We always want the polynomial in the numerator to have degree 1 less than the degree of the denominator. But we would end up determining b'=0 anyway.

\implies-3x^2+5x+6=ax(x+1)+b(x+1)+cx^2

If x=0, then b=6; if x=-1, then c=-2. Expanding everything on the right then gives

-3x^2+5x+6=ax^2+ax+bx+b+cx^2=(a-2)x^2+(a+6)x+6

which tells us a-2=-3 and a+6=5; in both cases, we get a=-1. Then

\dfrac{-3x^2+5x+6}{x^2(x+1)}=-\dfrac1x+\dfrac6{x^2}-\dfrac2{x+1}

as required.

5 0
4 years ago
Which choice is equivalent to the quotient below
Jobisdone [24]

Answer:

i think it is b but im not 100 percent sure

5 0
4 years ago
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