The second part of Rita's race is about 1800 meters at a speed of 150 meters per minute.
<h3>Speed</h3>
let
- distance covered in first Part = d1
- distance covered in second Part = d2
- distance covered in third Part = d3
- speed covered in first Part = s1
- speed covered in second Part = s2
- speed covered in third Part = s3
Distance in second Part:
d₃ = 15 x 300
= 4500 m
d₂ = 2/5 × d₃
= 2/5 x 4500
d₂ = 1800 meters
Speed in second part:
S₂ = 1800 m / 12 min
S₂ = 150 meters per minute
Learn more about distance:
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Answer:
Step-by-step explanation:
y = C(x - 1/3)(x - 1/3)(x + 1/4)
y = C(x² - 2/3x + 1/9)(x + 1/4)
y = C(x³ - 2/3x² + 1/4x² + 1/9x - 1/6x + 1/36)
y = C(x³ - 5/12x² - 1/18x + 1/36)
now to account for the y intercept (x = 0)
-3 = C((0)³ - 5/12(0)² - 1/18(0) + 1/36)
-3 = C(1/36)
C = -108
distribute the C term across all variables.
y = -108x³ + 45x² + 6x - 3
we can verify our solution using a plotting calculator.
I am not sure about that but your answer might be x=3 and y=0
Hope it helps : )
To find the probability of pulling something first take note of the total number and the amount of which you want to select.
100 and 10
Now set them up as a fraction
10/100 and simplify
1/10 or 10%
