Can someone tell me why is nobody helping me in this app come on y’all help

Mathematics

1 answer:

Mama L [17]3 years ago

8 0

Answer:

x = 3/2

Step-by-step explanation:

7/3 = (x + 2)/x

7x = 3(x + 2)

7x = 3x + 6

4x = 6

x = 6/4 = 3/2

There, someone helped you. Now could you do it alone next time?

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I ate 8/15 of the total amount of soup, then 140 ml of it remained in the bowl. how many milliliters of soup were there in the b

charle [14.2K]

Let t=original amount of soup

8/15 of t is 140
“Of” means multiply, “is” means equal to
Therefore
8/15t=140
t=140*15/8
t=262.5

Hope this helped :)

4 0

2 years ago

An isosceles right triangle has a hypotenuse of length e. Select all that are true for the triangle.

____ [38]

<h3>2 Answers: </h3>

Choice C) Leg length = $\frac{e\sqrt{2}}{2}$
Choice E) Area = $\frac{e^2}{4}$

Note: if the formulas don't load properly, then you may need to refresh the page.

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Explanation:

For any 45-45-90 right triangle, the hypotenuse H is always sqrt(2) times the leg L

In terms of symbols, we can say

$H = L*\sqrt{2}$

We're told the hypotenuse is e, so H = e

Let's solve for L in terms of e

$H = L*\sqrt{2}\\\\e = L*\sqrt{2}\\\\L*\sqrt{2} = e\\\\L = \frac{e}{\sqrt{2}}\\\\$

Now let's multiply top and bottom by $\sqrt{2}$ to rationalize the denominator

$L = \frac{e}{\sqrt{2}}\\\\L = \frac{e\sqrt{2}}{\sqrt{2}*\sqrt{2}}\\\\L = \frac{e\sqrt{2}}{\sqrt{2*2}}\\\\L = \frac{e\sqrt{2}}{\sqrt{4}}\\\\L = \frac{e\sqrt{2}}{2}\\\\$

If the hypotenuse is e, then the length of each leg is $\frac{e\sqrt{2}}{2}$

This matches with choice C, which is one of the two answers. This allows us to rule out choices A and B, as those expressions are not equivalent to the expression for choice C.

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The two legs of any right triangle form the base and height. The order doesn't matter. The base is always perpendicular to the height. In a right triangle, the two legs are always perpendicular.

The base and height are $\frac{e\sqrt{2}}{2}$ each.

The area of the triangle is...

$\text{Area} = \frac{1}{2}*\text{base}*\text{height}\\\\\text{Area} = \frac{1}{2}*\frac{e\sqrt{2}}{2}*\frac{e\sqrt{2}}{2}\\\\\text{Area} = \frac{e\sqrt{2}*e\sqrt{2}}{2*2*2}\\\\\text{Area} = \frac{e*e\sqrt{2*2}}{2*2*2}\\\\\text{Area} = \frac{e^2\sqrt{4}}{2*2*2}\\\\\text{Area} = \frac{e^2*2}{2*2*2}\\\\\text{Area} = \frac{e^2}{2*2}\\\\\text{Area} = \frac{e^2}{4}\\\\$