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Lemur [1.5K]
3 years ago
8

n Pensacola, Florida, the average rainfall in the month of July is $7.40$ inches. By October, the average rainfall decreases by

$35\%$ . By December, the average rainfall drops another $0.66$ inches.
Mathematics
1 answer:
erma4kov [3.2K]3 years ago
8 0

Answer:

Olani???

Why are you here?

(East harlem scholars academy teacher)

Step-by-step explanation:

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Why might a researcher use a sample rather than an entire population for their study?
cestrela7 [59]

Answer:

c

Step-by-step explanation:

its easier to take a group of 100 or something random people than a whole population.

6 0
3 years ago
Professional plumbers suggest that a sewer pipe should be sloped 0.25 inch for every foot. find the recommended slope for a sewe
erik [133]

We have been given that professional plumbers suggest that a sewer pipe should be sloped 0.25 inch for every foot.

Therefore, we can find the slope as:

\text{Slope}=\frac{0.25\text{ inch}}{\text{1 foot}}=\frac{0.25\text{ inch}}{\text{12 inch}}

\text{Slope}=\frac{0.25}{12}=\frac{25}{1200}=\frac{1}{48}

Therefore, the recommended slope for a sewer pipe is \frac{1}{48}


5 0
3 years ago
You work at a pioneer historical site. On this site you have handcarts. One cart has a handle that connects to the center of the
Gelneren [198K]

Answer:

a)  see below

b)  radius = 16.4 in (1 d.p.)

c)  18°. Yes contents will remain. No, handle will not rest on the ground.

d)  Yes contents would spill.  Max height of handle = 32.8 in (1 d.p.)

Step-by-step explanation:

<u>Part a</u>

A chord is a <u>line segment</u> with endpoints on the <u>circumference</u> of the circle.  

The diameter is a <u>chord</u> that passes through the center of a circle.

Therefore, the spokes passing through the center of the wheel are congruent chords.

The spokes on the wheel represent the radii of the circle.  Spokes on a wheel are usually evenly spaced, therefore the congruent central angles are the angles formed when two spokes meet at the center of the wheel.

<u>Part b</u>

The <u>tangent</u> of a circle is always <u>perpendicular</u> to the <u>radius</u>.

The tangent to the wheel touches the wheel at point B on the diagram.  The radius is at a right angle to this tangent.  Therefore, we can model this as a right triangle and use the <u>tan trigonometric ratio</u> to calculate the radius of the wheel (see attached diagram 1).

\sf \tan(\theta)=\dfrac{O}{A}

where:

  • \theta is the angle
  • O is the side opposite the angle
  • A is the side adjacent the angle

Given:

  • \theta = 20°
  • O = radius (r)
  • A = 45 in

Substituting the given values into the tan trig ratio:

\implies \sf \tan(20^{\circ})=\dfrac{r}{45}

\implies \sf r=45\tan(20^{\circ})

\implies \sf r=16.37866054...

Therefore, the radius is 16.4 in (1 d.p.).

<u>Part c</u>

The measure of an angle formed by a secant and a tangent from a point outside the circle is <u>half the difference</u> of the measures of the <u>intercepted arcs</u>.

If the measure of the arc AB was changed to 72°, then the other intercepted arc would be 180° - 72° = 108° (since AC is the diameter).

\implies \sf new\: angle=\dfrac{108^{\circ}-72^{\circ}}{2}=18^{\circ}

As the handle of the cart needs to be no more than 20° with the ground for the contents not to spill out, the contents will remain in the handcart at an angle of 18°.

The handle will not rest of the ground (see attached diagram 2).

<u>Part d</u>

This can be modeled as a right triangle (see diagram 3), with:

  • height = (48 - r) in
  • hypotenuse ≈ 48 in

Use the sin trig ratio to find the angle the handle makes with the horizontal:

\implies \sf \sin (\theta)=\dfrac{O}{H}

\implies \sf \sin (\theta)=\dfrac{48-r}{48}

\implies \sf \sin (\theta)=\dfrac{48-45\tan(20^{\circ})}{48}

\implies \theta = 41.2^{\circ}\:\sf(1\:d.p.)

As 41.2° > 20° the contents will spill out the back.

To find the <u>maximum height</u> of the handle from the ground before the contents start spilling out, find the <u>height from center of the wheel</u> (setting the angle to its maximum of 20°):

\implies \sin(20^{\circ})=\dfrac{h}{48}

\implies h=48\sin(20^{\circ})

Then add it to the radius:

\implies \sf max\:height=48\sin(20^{\circ})+45\tan(20^{\circ})=32.8\:in\:(1\:d.p.)

(see diagram 4)

------------------------------------------------------------------------------------------

<u>Circle Theorem vocabulary</u>

<u>Secant</u>: a straight line that intersects a circle at two points.

<u>Arc</u>: the curve between two points on the circumference of a circle

<u>Intercepted arc</u>: the curve between the two points where two chords or line segments (that meet at one point on the other side of the circle) intercept the circumference of a circle.

<u>Tangent</u>: a straight line that touches a circle at only one point.

7 0
2 years ago
How many triangles can be constructed with sides measuring 5 m, 16 m, and 5 m?
lianna [129]
There are two measures 5 cm then the triangle will be isosceles or 16 is far beyond 5 + 5 = 10 so we cannot build any triangle so te answer is <span>B none
</span>
3 0
3 years ago
-21 = 7(3 - x)<br><br> Please help. You have to use distributive property to solve.
OlgaM077 [116]
The answer is 6


hope this helps !!
4 0
2 years ago
Read 2 more answers
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