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3 years ago

8

n Pensacola, Florida, the average rainfall in the month of July is $7.40$ inches. By October, the average rainfall decreases by

$35\%$ . By December, the average rainfall drops another $0.66$ inches.

1 answer:

erma4kov [3.2K]3 years ago

8 0

Answer:

Olani???

Why are you here?

(East harlem scholars academy teacher)

Step-by-step explanation:

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-14 and 5 (-14+5 = -9) and -14*5) = -70

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3 years ago

Divide the given polynomial by the given monomial.

Ostrovityanka [42]

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2 years ago

16-z=12 solve equation

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3 years ago

josh is on his way home in his car. He has driven 18 miles so far,which is two- thirds of the way home, what is the total length

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3 years ago

Messages arrive to a computer server according to a Poisson distribution with a mean rate of 11 per hour. Determine the length o

Zarrin [17]

Answer:

The length of the interval during which no messages arrive is 90 seconds long.

Step-by-step explanation:

Let <em>X</em> = number of messages arriving on a computer server in an hour.

The mean rate of the arrival of messages is, <em>λ</em> = 11/ hour.

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em> = 11.

The probability mass function of <em>X</em> is:

$P(X=x)=\frac{e^{-11}11^{x}}{x!};\ x=0,1,2,3....$

It is provided that in <em>t</em> hours the probability of receiving 0 messages is,

P (X = 0) = 0.76

Compute the value of <em>t</em> as follows:

$P(X=0)=\frac{e^{-11\times t}(11\times t)^{0}}{0!}\\0.76=e^{-11\times t}\\\ln(0.76)=-11\times t\\t=-\frac{\ln(0.76)}{11} \\=0.025\ hours\\\approx90\ seconds$

Thus, the length of the interval during which no messages arrive is 90 seconds long.

6 0

3 years ago