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3 years ago

Which expression is equal to (6x−4)(3x−1)?

Mathematics

1 answer:

Natali5045456 [20]3 years ago

3 0

Answer:

$(6x-4)(3x-1) = 18x^2 - 18x + 4$ is the required simplification.

Step-by-step explanation:

Here, the given expression is (6x−4)(3x−1).

By DISTRIBUTIVE PROPERTY of numbers:

A ( B + C ) = AB + AC

Simplifying the given expression, we get:

$(6x-4)(3x-1) = 6x(3x-1)-4(3x-1)\\= 6x(3x) -1(6x) -4(3x) +4\\=18x^2 - 6x - 12x + 4\\18x^2 - 18x + 4$

or, $(6x-4)(3x-1) = 18x^2 - 18x + 4$

Hence the given expression is simplified.

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Answer

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3 years ago

87 is what percent of 66

kozerog [31]

131.818182% and can round to 131.82

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2 years ago

I don’t understand how to find the height

ANTONII [103]

Answer:

height, x is 235 ft

Step-by-step explanation:

From trigonometric ratios:

$\cos( \theta) = \frac{adjacent}{hypotenuse}$

but:

$\theta = 90 \degree - 36 \degree \\ \theta = 54 \degree$

adjacent is x

hypotenuse is 400 ft

$\ \cos ( 54 \degree) = \frac{x}{400} \\ \\ x = 400 \ \cos (54 \degree) \\ x = 235 \: \: feet$

8 0

3 years ago

Read 2 more answers

Need help with this asap please

Rainbow [258]

Since they are similar, that means they are proportionally the same.
So KL is similar to PN
JL is similar to PM

So,
You need to find how much bigger is the second triangle from first.
It is proportionally scaled up.

KL/JL = PN/ PM

You basically put in order of triangles. Left triangle on left side of equal sign and right triangle on right side of equal sign. You put in denominator the similar sides and numerator the similar sides (the side that is similar to the side of the other triangle)

5/6 = PN / 9
Cross-multiply
PN * 6 = 5*9
6PN = 45
PN =45/6

PN =7.5

5 0

2 years ago

How many x intercepts does the graph of y =|x-2|+12

WARRIOR [948]

Answer:

The graph not have x-intercepts

Step-by-step explanation:

we know that

The x-intercept is the value of x when the value of y is equal to zero

we have

$y=\left|x-2\right|+12$

This is the equation of an absolute value in vertex form open upward

The vertex is the point (2,12)

The y-coordinate of the vertex is above the x-axis and the graph open upward

That means ----> The graph do not intersect the x-axis

therefore

The graph not have x-intercepts

Verify

For y=0

substitute in the equation

$0=\left|x-2\right|+12$

$\left|x-2\right|=-12$ ----> is not true

The left side of the equation cannot be a negative number

The equation not have solution for y=0

therefore

The graph not have x-intercepts

see the attached figure to better understand the problem

8 0

3 years ago