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cupoosta [38]
2 years ago
15

The table below shows 6 students' overall averages and their averages

Mathematics
2 answers:
kvasek [131]2 years ago
4 0

Answer: choice 2 - it is close to 1

Step-by-step explanation:

vivado [14]2 years ago
3 0

Answer:

yysududufududydhxududurfuuru

udududurudud

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g In American roulette, the wheel has the 38 numbers, 00, 0, 1, 2, ..., 34, 35, and 36, marked on equally spaced slots. If a pla
earnstyle [38]

Answer:

The expected value for the player to play one time is -$0.05.

Step-by-step explanation:

The expected value of a random variable <em>X</em> is given by the formula:

E(X)=\sum x\cdot P(X)

The American roulette wheel has the 38 numbers, {i = 00, 0, 1, 2, ..., 34, 35, and 36}, marked on equally spaced slots.

The probability that the ball stops on any of these 38 numbers is same, i.e.

P (X = i) = \frac{1}{38}.

It is provided that a a player bets $1 on a number.

If the player wins, the player keeps the dollar and receives an additional $35.

And if the player losses, the dollar is lost too.

So, the probability distribution is as follows:

<em>     X </em>: $35      -$1

P (<em>X</em>) :   \frac{1}{38}         \frac{37}{38}  

Compute the expected value of the game as follows:

E(X)=\sum x\cdot P(X)

         =[\$35\times \frac{1}{38}]+[-\$1\times \frac{37}{38}]\\\\=\frac{\$35-\$37}{38}\\\\=-\frac{\$2}{38}\\\\=-\frac{1}{19}\\\\=-0.052632\\\\\approx -\$0.05

Thus, the expected value for the player to play one time is -$0.05.

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