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Ksenya-84 [330]
3 years ago
7

I need help with this guys and step by step solution.

Mathematics
1 answer:
choli [55]3 years ago
5 0
A, b, c, D let me know if this helps
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...im failing please
Taya2010 [7]

Answer:

top row on 9 page; 9) 53/5 10) 26/4 11) 37/4

bottom row on 9 page; 9) 8 and 1/7 10) 6 and 3/4 11) 1 and 1/3

top row on 3 page; 3) 2 and 2/7 4) 5 and 3/4 5) 8 and 1/10

bottom row on 3 page; 3) 4/3 4) 3/2 5) 12/5

top row on 12 page; 12) 21/10 13) 62/6 14) 57/6

bottom row on 12 page; 12) 1 and 9/10 13) 10 and 1/2 14) 3 and 3/8

Step-by-step explanation:

You never specified if these had to be simplified or turned into a fraction, so I just simplified them. That's about it.

I hope this helps :)

7 0
3 years ago
Use the function below to find f(–4). f(x) = 2x
Tcecarenko [31]
Replace x with -4 so it would be:
f(-4)= 2(-4)=-8
-8 is your answer
6 0
3 years ago
Read 2 more answers
Solve this please, and quick
rosijanka [135]
Error: They subtracted 9x from both sides when they should have subtracted 12. You can’t subtract unlike terms
Correct: x=-5/16
Subtract 12 from both sides to get -5 on the left and add 7x and 9x to get 16x. Divide both sides by 16 to isolate x.
8 0
3 years ago
Read 2 more answers
If the sun approximately 1.5 * 10/11 meters from Earth how long does it take for light to reach earth
Agata [3.3K]
The sun is 1.5*10^11 METERS from the Earth. In that case it takes approximately 8.3 minutes for sunlight to reach Earth. 
<span>t=(1.5*10^11/3.0*10^8)/60=8.33 minutes </span>
<span>If you did want a hypothetical that puts the Earth at 1.5*10^11 kilometers from the sun, then it would take 8333.3 minutes for the sunlight to reach the "Earth's" surface. </span>
<span>t=(1.5*10^14/3.0*10^8)/60=8333.3 minute</span>
4 0
4 years ago
The top of a dam has an angle of elevation of 1.1 radians from a point on a river. Measuring the angle of elevation to the top o
Pepsi [2]

Answer: 335ft

Step-by-step explanation:

The tangent of the angle of elevation is the ratio of the dam height h to the horizontal distance downriver of the observer. This gives us two equations for the height:

h= atan(1.1) = (155+a) tan(0.8)

⟹a= h/tan(1.3), 155+a= h/tan(0.8).

Subtracting the first equation from the second,

155=(155+a)−a =h/tan(0.8)−h/tan(1.1)

=h(1/tan(0.8)−1/tan(1.1)).

Solving for h,

h=155 ft (1tan(0.8)−1tan(1.1))−1

155(0.9713 - 0.5090)^-1

155(2.1631) ≈335 ft .

7 0
3 years ago
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