Answer:
6(x - 1)(3x + 1)
Step-by-step explanation:
Given
18x² - 12x - 6 ← factor out 6 from each term
= 6(3x² - 2x - 1) ← factor the quadratic
Consider the factors of the product of the x² term and the constant term which sum to give the coefficient of the x- term
product = 3 × - 1 = - 3 and sum = - 2
The factors are - 3 and + 1
Use these factors to split the x- term
3x² - 3x + x - 1 ( factor the first/second and third/fourth terms )
= 3x(x - 1) + 1(x - 1) ← factor out (x - 1)
= (x - 1)(3x + 1)
Hence
18x² - 12x - 6 = 6(x - 1)(3x + 1) ← in factored form
Use x+2y=8
Subtract 2y to make
x=8-2y
Plug this in to the other equation
3(8-2y)+2y=6
Distribute the 3
24-6y+2y=6
Combine like terms
24-4y=6
Solve
18/4=y, 9/2=y
Plug and solve for x
X+2y=8
X+(2*9/2)=8
X+9=8
X=-1
Let's take the number as x.
two-fifths of a number = 2x / 5
decreased by 3 = (2x/5) - 3
(2x/5) - 3
(2*25/5) - 3
(2*5) - 3
10 - 3
7
Multiply the denominators together and the numerators together and you have your answer
