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frozen [14]
3 years ago
15

Write (p^2)^3 without exponents

Mathematics
1 answer:
Rasek [7]3 years ago
4 0

Answer:

p*p*p*p*p*p*p*p*p

Step-by-step explanation:

(p^2)^3

2^3=8

=p^8

p^8 = p*p*p*p*p*p*p*p

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Hiii can someone please help me with this math question
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I think you just need to draw a number line starting at one OR zero that goes up and explain why
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Look at the number sentence below. -26 + 75 =
Novosadov [1.4K]
-26+75=43 hope this helps


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1. Which of the following describes an argument based on the idea that if you have a few cases, you can draw a conclusion?
cluponka [151]

Answer:

B. Limited choice

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O
jekas [21]

Answer:

b= -8

Step-by-step explanation:

we have: 3y +12 = 6x <=> y + 4 = 2x <=> y= 2x - 4

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3 years ago
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Assume that the weight loss for the first month of a diet program varies between 6 pounds and 14 pounds, and is spread evenly ov
Llana [10]

Hello!

For this uniform distribution, the shape of the density function is a line. We can begin by identifying key elements of the distribution:

Range: 6 to 14 pounds

Formula of density function:

y = 1/Range

1 - (14 - 6) = 1/8 = 0.125

f(x) = 0.125

1)

P(x = 7)

A uniform distribution is a continuous distribution, so the probability of x being an EXACT value is approximately 0.

<u>This is the same as if we took the following integral. (Finding the area under a curve with the same start and end point)</u>
\int\limits^a_a {f(x)} \, dx  = 0

Therefore, P(x = 7) = 0.

2)
We can think of this as finding the area of a rectangle.

The width would be the difference between 8.25 pounds and 12 pounds:
W = 12 - 8.25 = 3.75

The height would be the function (y = .125), or:
h = .125

Using the equation for the area of a rectangle: (A = h * w)

A = 3.75 * .125 = 0.469

Thus, P(8.25 < x < 12) = 0.469

3)
To find the probability GREATER than 10.50 pounds, we can subtract this value from the max value for the width:
W = 14 - 10.50 = 3.50

The height is the same as above:
h = .125

Solve for the area:
A = 3.50 * .125 = 0.4375

P(x > 10.5) = 0.4375

5 0
2 years ago
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