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wlad13 [49]
3 years ago
13

Mark wants to cut a triangular patch to make an emblem. The pattern for

Mathematics
1 answer:
USPshnik [31]3 years ago
3 0

Answer:

The lengths of the other two sides should be 20 cm.

Step-by-step explanation:

Dimensions of the emblem triangle = 8,8 and 10

Longest side of the emblem ,L= 10 cm

Length of the longest side mark wants for his emblem , l= 25cm

One of the length of other side of an emblem = S = 8 cm

One of the length of other side of an emblem Mark making = s

The triangle of original emblem and emblem made by Mark will be similar , So;

\frac{L}{l}=\frac{S}{s}

\frac{10 cm}{25 cm}=\frac{8 cm}{s}

s=\frac{8cm\times 25 cm}{10 cm}=20 cm

The lengths of the other two sides should be 20 cm.

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Answer:

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3 0
3 years ago
Here are two rectangles.
Sophie [7]

Answer:

AB=9.5\ cm

Step-by-step explanation:

step 1

Find the length side PQ

we know that

The area of rectangle PQRS is given by

A=(PQ)(QR)

A=66\ cm^2

so

66=(PQ)(QR)

substitute the value of QR

66=(PQ)(12)

solve for PQ

PQ=66/12\\PQ=5.5\ cm

step 2

Find the length side AB

we know that

The perimeter of rectangle ABCD is given by

P=2(AB+BC)

we have

P=30\ cm\\BC=PQ=5.5\ cm

substitute

30=2(AB+5.5)

solve for AB

15=AB+5.5\\AB=15-5.5\\AB=9.5\ cm

6 0
3 years ago
What should be done to x^2 + 15x in order to create a perfect square?
lana [24]

\bf \qquad \textit{perfect square trinomial} \\\\ (a\pm b)^2\implies a^2\pm \stackrel{\stackrel{\text{\small 2}\cdot \sqrt{\textit{\small a}^2}\cdot \sqrt{\textit{\small b}^2}}{\downarrow }}{2ab} + b^2 \\\\[-0.35em] ~\dotfill

\bf x^2+15x+\boxed{?}^2\implies \stackrel{\textit{we know the middle term is}}{2\sqrt{x^2}\cdot \sqrt{\boxed{?}^2}\implies 2x\boxed{?}}\qquad then\qquad 2x\boxed{?}=15x \\\\\\ \boxed{?}=\cfrac{15x}{2x}\implies \boxed{?}=\cfrac{15}{2}\qquad \impliedby \textit{we should add that much \underline{squared}} \\\\[-0.35em] ~\dotfill\\\\ x^2+15x+\left( \cfrac{15}{2} \right)^2\implies \left(x+ \cfrac{15}{2} \right)^2

5 0
3 years ago
A line passes through (-8,3) and (-6,4).What is the equation of the line?
Komok [63]

Answer: The equation of the line that passes through the points

(-8,3) and (-6,4)

is

y=1/2x+7

Step-by-step explanation: First, let's find what m is, the slope of the line...

The slope of a line is a measure of how fast the line "goes up" or "goes down". A large slope means the line goes up or down really fast (a very steep line). Small slopes means the line isn't very steep. A slope of zero means the line has no steepness at all; it is perfectly horizontal.

For lines like these, the slope is always defined as "the change in y over the change in x" or, in equation form:

So what we need now are the two points you gave that the line passes through. Let's call the first point you gave, (-8,3), point #1, so the x and y numbers given will be called x1 and y1. Or, x1=-8 and y1=3.

Also, let's call the second point you gave, (-6,4), point #2, so the x and y numbers here will be called x2 and y2. Or, x2=-6 and y2=4.

Now, just plug the numbers into the formula for m above, like this:

m=  

4 - 3

-6 - -8

or...

m=  

1

2

or...

m=1/2

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

y=1/2x+b

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

(-8,3). When x of the line is -8, y of the line must be 3.

(-6,4). When x of the line is -6, y of the line must be 4.

Because you said the line passes through each one of these two points, right?

Now, look at our line's equation so far: y=1/2x+b. b is what we want, the 1/2 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (-8,3) and (-6,4).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!.

You can use either (x,y) point you want..the answer will be the same:

(-8,3). y=mx+b or 3=1/2 × -8+b, or solving for b: b=3-(1/2)(-8). b=7.

(-6,4). y=mx+b or 4=1/2 × -6+b, or solving for b: b=4-(1/2)(-6). b=7.

See! In both cases we got the same value for b. And this completes our problem.

7 0
3 years ago
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