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alexandr1967 [171]
2 years ago
8

Find the length of D. ​

Mathematics
1 answer:
defon2 years ago
6 0

Answer:

root 50

Step-by-step explanation:

Pythagorean theorem d is the hypotenuse

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Seth is using the figure shown below to prove Pythagorean Theorem using triangle similarity.
Arturiano [62]

The <em>Pythagorean</em> theorem is one that can be used to <u>determine</u> the <em>third</em> unknown side of a given <em>right-angled</em> triangle. Thus the answers required are:

  • A <em>pair</em> of <u>similar</u> triangles formed are ΔABD and ΔADC
  • Segment AD is a perpendicular <em>bisector</em> of segment BC, and also <u>bisects</u> angle A in two equal measures
  • Segment AD = 3

A <em>right-angled</em> triangle is one which has the <em>measure</em> of one of its internal angles <u>equal</u> to 90^{o}. Thus to determine the <em>value</em> of one of its unknown sides, the <em>Pythagoras theorem</em> can be used.

<em>Pythagora theorem</em> states that: for a <u>right-angled</u> triangle,

/Hypotenus/^{2} = /Adjacent 1/^{2} + /Adjacent 2/^{2}

Thus from the given question, we have;

Part A: A <em>pair</em> of <u>similar</u> triangles formed are ΔABD and ΔADC.

Part B: In the given triangle, segment AD is a <em>perpendicular bisector</em> of segment BC. Thus segment AD also <u>bisects</u> angle A in two equal measures. So triangle ABC is now <em>divided</em> into <u>two</u> equal pairs i.e ΔABD and ΔADC.

Part C: Given that: If DB = 9 and DC = 4, find the length of segment DA.

Let segment AD be represented by x, so that;

from ΔABC,

/Hypotenus/^{2} = /Adjacent 1/^{2} + /Adjacent 2/^{2}

/13/^{2} = /Adjacent 1/^{2} + /Adjacent 2/^{2}

Thus the appropriate Pythagorean triple for this question is 5, 12, 13.

So that AB = 12, AC = 5 and BC = 13

Let segment AD be represented by x.

Thus from triangle ADC, applying the Pythagoras theorem we have;

5^{2} = x^{2} + 4^{2}

25 - 16 = x^{2}

x^{2} =   9

x = 3

Therefore, <u>segment</u> AD is 3.

For more clarifications on Pythagoras theorem, visit: brainly.com/question/343682

#SPJ1

Kindly contact a 1-on-1 tutor if more explanations are needed.

6 0
1 year ago
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