Question

I will mark you brainliest once you get the answer correct first!!

Answer 1

Given:

A composed figure of a rectangle, semicircle and another semicircle removed.

To find:

The area of the given figure.

Solution:

From the given figure it is clear that the diameter of semicircle and removed semicircle are same, i.e. 8 cm.

Since the diameter of semicircle are equal, therefore their area is also equal.

The area of the given figure is:

A = Area of the rectangle - Area of removed semi circle + Area of semicircle

A = Area of the rectangle - Area of semicircle + Area of semicircle

A = Area of the rectangle

We know that, the area of a rectangle is

$A=length\times width$

The length of the rectangle is 14 units and width is 8 units. So, the area of composed figure is

$A=14\times 8$

$A=112$

Therefore, the area of the combined figure is 112 sq. units.