Answer:
||| First row: 11 -20 23 ||| Second row: -21 5 -24 ||| Third row: 6 9 -14 |||
Step-by-step explanation:
I wish I could explain it better, but all I did was plug it into matrix A on:
https://atozmath.com/matrix.aspx?q=minor
I pressed "find" without changing any of the settings, and scrolled down until I saw what was in the attached screenshot.
Each of the rows correspond to the first, second, and third answers, as you can see.
I hope this helps!
<u>Given</u>–
AB = 12 Cm
CD = 14 Cm
PO = 10 Cm
AP = 1/2 × 12 = 6 Cm
<u>Construction</u>–
Draw NO such that it is the perpendicular bisector of CB.
Hence,
ND = 1/2 × 14 = 7 Cm
To Find,
Measure of NO
<u>Solution</u>,
Here, PO Perpendicular to AB
Hence, APO is a right-angled triangle–
AO² = PO² + AP²
Or, AO² = 10 ² + 6 ²
Or, AO² = 36 + 100
Or, AO = √136 Cm
Or, AO = 11.66 Cm
Also, AO = OD = 11.66 Cm
( Radius of the same circle )
Now, in triangle OND,
OD² = ON² + ND ²
Or, 11.66 ² = ON² + 7²
Or, 136 = ON² + 49
Or, ON ² = 136 – 49
Or, ON ² = 87
Or, ON ² = √87
Or, ON = 9.3 Cm
Therefore, the appropriate length from center to CD is 9.3 Cm.
-2+✓34, -2-✓34.
20 characters ahhh
I may think is 18. Hope this helps.