To find our solution, we can start off by creating a string of 27 boxes, all followed by the letters of the alphabet. Underneath the boxes, we can place 6 pairs of boxes and 15 empty boxes.The stars represent the six letters we pick. The empty boxes to the left of the stars provide the "padding" needed to ensure that no two adjacent letters are chosen. We can create this -

Thus, the answer is that there are

ways to choose a set of six letters such that no two letters in the set are adjacent in the alphabet. Hope this helped and have a phenomenal New Year!
<em>2018</em>
Answer:
E, A, F
Step-by-step explanation:
Answer:
Jogging 6th time.
Step-by-step explanation:
We have been given that Vicki started jogging the first time she ran she ran 3/16 mile the second time she ran 3/8 mile and the third time she ran 9/16 mile.
We can see that the distance Vicki covers each time forms a arithmetic sequence, where 1st term is 3/16.
We know that an arithmetic sequence is in form
, where,
= nth term of sequence,
= 1st term of sequence,
n = Number of terms in sequence,
d = Common difference.
Let us find common difference of our given sequence as:

Since Vicki needs to cover more than 1 mile, so we nth term of sequence should be greater than 1.

Let us solve for n.





We can also write next terms of our sequence as:

Therefore, Vicki will run more than 1 mile when she is jogging for 6th time.
Answer:
answer is b
Step-by-step explanation:
hope it helps!!!