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2 years ago

I NEED HELP WITH NUMBER 3 PLEASE HELP I WILL MARK BRAINLIEST. NO LINKS. IM BEING TIMEDDDD

Mathematics

1 answer:

ra1l [238]2 years ago

3 0

Answer:

210.65 ft

round as needed

Step-by-step explanation:

Law of Cosines

c^2 = a^2 + b^2 - 2abCosC

c^2 = 125^2 + 210^2 - 2(125)(210)Cos73

c^2 = 15,625 + 44,100 - 15349.5

c^2 = 44,375.5

c = 210.654931107724132

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2 years ago

Solve 2cos ²y -siny -1=0 for 0° ≤y≤360°

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2 years ago

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nikitadnepr [17]

Answer:

p = 7

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set the expressions = to each other

4(n+7) = 4(n+p)

distribute the 4 on both sides(multiplying the numbers on the inside)

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subtract the 4n from the right and left

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3 0

3 years ago

A mixture of gases was found to have a total pressure of 950 mmhg gas number 1 has a pressure of 335 mmhg gas number 2 has a pre

frez [133]

Answer:

The pressure exerted by gas number 3 is 159 mmHg

Step-by-step explanation:

To answer this question, the law to Use is Dalton’s law of partial pressure

Dalton’s law of partial pressure states that for a mixture of gases which do not mix, the total pressure exerted by such gases is equal to the sum of the individual pressure.

Now for the three gases, the total pressure Pt is equal to P1 + P2 + P3

Now we have Pt = 950 mmHg, P1 = 335 mmHg and P2 = 456 mmHg

P3 = Pt-P1-P2

Plugging the values above, we have ; 950-335-456 = 159 mmHg

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2 years ago