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3 years ago

Please help me on this one

Mathematics

1 answer:

Marina CMI [18]3 years ago

3 0

It’s c, 4 divided by 4 is .25 which gives you a 25 percent chance to get either

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How can the additive inverse be used to evaluate the problem below?

kondaur [170]

Answer:

Step-by-step explanation:

HEYAA!!!!!

OPTION D

To get the additive inverse of a positive number you put a minus in front of it and to get the additive inverse of a negative number, you remove the minus to make it a positive number.

because when u see the equation u can see it is -3-(-6)

which if u solve it the answer is -3+6=3

so the correct option is (D)

HOPE U UNDERSTOOD

4 0

4 years ago

Read 2 more answers

What is the general equation for direct<br> variation?

BARSIC [14]

Answer:

☆ y=kx

Example: if we have x= 3 and y= 15

Find y?

y= kx

*We know that y= 15 and x= 3

So,

15=k(3)

15=3k

*divide 3 from both sides

K=5

y=5x

y=5(5)=25

☆▪☆▪☆▪☆▪☆

Hope it helps..

Have a great day!!

4 0

3 years ago

Moden is short for?

son4ous [18]

Answer:

Modulator Demodulator

Step-by-step explanation:

5 0

3 years ago

Help and show all work please

Anarel [89]

Answer:

1-3

2-8.9

3-6.3

4-26

5-7.8

6-17

7-10

8-32

9-7.9

10-13.2

11- is a right triangle

12- is not a right triangle

13- is a right triangle

14- is not a right triangle

15- is a right triangle

16- is not a right triangle

Step-by-step explanation:

I will do the rest it will just take me some time. I will also give you

step by step at the end.

7 0

3 years ago

Read 2 more answers

Based on the figure below, the ratio of x/y is equivalent to which trigonometric function?

Ede4ka [16]

Answer: OPTION D.

Step-by-step explanation:

For this exercise it is important to remember the following Trigonometric Functions:

$sin\alpha =\frac{opposite}{hypotenuse}\\\\cos\alpha =\frac{adjacent}{hypotenuse}\\\\tan\alpha =\frac{opposite}{adjacent}\\\\sec\alpha =\frac{hypotenuse}{adjacent}\\\\csc\alpha =\frac{hypotenuse}{opposite}\\\\cot\alpha =\frac{adjacent}{opposite}$

Knowing this, we can identify that:

$cosA=\frac{AC}{AB}=\frac{x}{AB}\\\\sinB=\frac{AC}{AB}=\frac{x}{AB}\\\\secA=\frac{AB}{AC}=\frac{AB}{x}\\\\tanB=\frac{AC}{BC}=\frac{x}{y}$

Therefore, the ratio $\frac{x}{y}$ is equivalent to this Trignometric function:

$tanB=\frac{x}{y}$

8 0

4 years ago