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Aleksandr-060686 [28]
3 years ago
8

3. At a bargain store, Jamal bought 2 items that each cost the same amount. Isaiah bought 3 items that each cost the same amount

, but each was $2.25 less than the items that Jamal bought. Both Jamal and Isaiah paid the same amount of money. What was the individual cost of each person's items?
(5 points) (a) Write an equation. Let x represent the cost of one of Jamal's items. Your equation will have an x term on both sides.

(2 pts) (b) Solve the equation. Show your work.

(3 pts) (c) Check your solution. Show your work. (1 pt bonus)


​
Mathematics
1 answer:
coldgirl [10]3 years ago
7 0

Answer:

  • $6.75 and $4.50

Step-by-step explanation:

a) <u>Jamal spent:</u>

  • 2x

<u>Isaiah spent:</u>

  • 3 (x - 2.25)

<u>The equation is:</u>

  • 2x = 3(x - 2.25)

b) <u>Solving the equation</u>

  • 2x = 3x - 6.75
  • 3x - 2x = 6.75
  • x = 6.75

c) <u>Jamal's items cost </u>

  • $6.75 each

<u>Isaiah's items cost </u>

  • $6.75 - $2.25 = $4.50 each
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Toshi must begin his walk at 11:00 AM in order that he can return by 8:00 PM.

Step-by-step explanation:

Since the Gotemba walking trail up Mount Fuji is about 9km long, and walkers need to return from the 18km walk by 8pm, if Toshi estimates that he can walk up the mountain at 1.5km / h on average, and down at twice that speed , these speeds taking into account meal breaks and rest times, to determine what is the latest time he can begin his walk so that he can return by 8pm the following calculation must be performed:

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Answer:

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Step-by-step explanation:

To find a particular solution to a differential equation by inspection - is to assume a trial function that looks like the nonhomogeneous part of the differential equation.

(a) Given y'' + 2y = 14.

Because the nonhomogeneus part of the differential equation, 14 is a constant, our trial function will be a constant too.

Let A be our trial function:

We need our trial differential equation y''_p + 2y_p = 14

Now, we differentiate y_p = A twice, to obtain y'_p and y''_p that will be substituted into the differential equation.

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