
is the answer to your question
:
You put 57 in F (on the left side)
You put 49 in S ( on the right side)
Have a great day
area of rectangle = L x w
area = 8 sq ft
w= L-2
so 8 = L *L-2
8 = l^2-2l
l^2 -2l-8 = 0
(l-4) (l+2)=0
Length = 4 feet
Width = 2 feet
Answer:
Step-by-step explanation:
10=z+6
subtract 6 from both sides
4=z
z=4
Answer:
Bar will not fit in the box.
Step-by-step explanation:
Given:
Length = 9 in
Width = 8 in
Height = 3 in
Length of bar = 13 in
Find:
Bar fit in box or not
Computation:
If length of bar is equal to length of diagonal than it will fit in box.
Diagonal of a cuboid = √l² + b² + h²
Diagonal of a cuboid = √9² + 8² + 3²
Diagonal of a cuboid = √81 + 64 + 9
Diagonal of a cuboid = √154
Diagonal of a cuboid = 12.40 in
Diagonal of a cuboid < Length of bar
So,
Bar will not fit in the box.