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Alecsey [184]
3 years ago
6

Across which axis was point A reflected​

Mathematics
1 answer:
Snezhnost [94]3 years ago
4 0

Answer:

When point A with coordinates (0, -1) is reflected across the x-axis and mapped onto point A', the coordinates of A' will be (0, 1).

i.e A'(0, 1) is the image of point A after a reflection.

Hence, point A is reflected across the x-axis.

Step-by-step explanation:

When we reflect a point A across the x-axis, the value of 'y' gets negated, but the value of 'x' remains unchanged.

In other words, when point P with coordinates (x, y) is reflected across the x-axis and mapped onto point P', the coordinates of P' will be (x, -y).

Thus, the rule is:

P(x, y) → P'(x, -y)

Thus, when point A with coordinates (0, -1) is reflected across the x-axis and mapped onto point A', the coordinates of A' will be (0, 1).

i.e A'(0, 1) is the image of point A after a reflection.

Hence, point A is reflected across the x-axis.

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PLEASE SOLVE THIS :(<br>​
Lesechka [4]

Answer:

10.5 %

<u>Skills needed: Financial Math Essentials</u>

Step-by-step explanation:

1) First, before getting started, let's assume the price of the product is x. This variable will be used a lot throughout the problem (x).

2) Marking a price above means increasing the price in order to make money off of the purchased product. When raising something by y percent, the new price would be x + \frac{y}{100}*x.

---> In this case, the price increased by \textbf{30} percent.

This means that it would be: x+\frac{30}{100}x = x+0.3x=1.3x

New price is: 1.3x

3) The shopkeeper is then offering a \textbf{15} percent discount off of this marked price. When offering a b percent discount price, the new price (with discount), expressed algebraically is: a-\frac{b}{100}a

---> the expression above simplifies to (1-\frac{b}{100})a

In this case, a=1.3x, b=15

---> (1-\frac{15}{100})*1.3x = (1-0.15)*1.3x=0.85*1.3x=1.105x

This means that x, with discount, has been raised \textbf{10.5 percent}.

10.5 % is the profit percent

(The profit percent being the final marked up price - purchased price)

5 0
2 years ago
PLEASEEE HELP NOBODY IS ANSWERING ME RIGHT ALSO I AM USING UP THE LAST OF MY PoiNTS TO ASK THIS QUESTION !!! Determine the verte
irga5000 [103]

Answer:

D.

Step-by-step explanation:

with questions like this try using Desmos

8 0
2 years ago
Read 2 more answers
Solve 8(m - 5 ) = 48
Art [367]

Answer

1)8(m -5 ) = 48 \\ 8m - 40 = 48 \\ 8m = 48 + 40 \\ 8m = 88 \\  \frac{8m}{8}  =  \frac{88}{8}  \\ m = 11

2)x + 7 = 13 \\ x = 13 - 7 \\ x = 6

3)3h - 5 = 12 \\ 3h = 12 + 5 \\ 3h = 17 \\  \frac{3h}{3}  =  \frac{17}{3}  \\ h = 5 \frac{2}{3}

Hope this helps you.

Let me know if you have any other questions :-):-)

4 0
2 years ago
Read 2 more answers
(04.02 LC)
True [87]
The graph is the horizontal line:

y=3  it has a slope of zero.

Function 2 is

y=3x+1, it is in slope-intercept form, y=mx+b where m is the slope and b is the y=intercept so in this case it has a slope of 3.

So the difference in slopes is 3-0=3
3 0
3 years ago
The cargo carrying part of Billy‘s truck has a length of 8.3 m a width of 3 m and a height of 4.2 m. What is the maximum volume
madam [21]
You're really just finding the volume of the cargo-carry part.

V= L x W x H

V= 8.3m x 3m x 4.2m

V= 104.58 m3 or 105 m3 (rounded)

ANSWER: The maximum volume of sand Billy's truck can carry is about 105 m3.
8 0
3 years ago
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