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valentinak56 [21]
3 years ago
7

What is class standing if student who is 21 in a class of 570?

Mathematics
1 answer:
tiny-mole [99]3 years ago
4 0

Answer: 27 hope it helps also your question is unclear -.-

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Solve for x and y simultaneously:<br> X-2y=3<br> 4xsquared-5xy+6y=3
Mkey [24]
X - 2y = 3
<span>4x^2 - 5xy + 6y = 3
lets solve for x the first and substitute in the second:
x = 3 + 2y
4(</span>3 + 2y)^2 - 5(3 + 2y)y + 6y = 3
4(9 + 12y + 4y^2) - 15y - 10y^2 = 3
36 + 48y +16y^2<span> - 15y - </span><span>10y^2 = 3
6y^2 + 33y + 33 = 0
we can solve using the general quadratic formula:
y = (-33 +- </span>√(33^2 - 4*6*33)<span>)/12
</span>y = (-33 +- √(297)<span>)/12
</span>so there are 2 solutions for y:
y1 = (-33 + √(297)<span>)/12
</span>y2 = (-33 - √(297)<span>)/12
</span>pick one and then substitute the y value in the first equation to find x
4 0
4 years ago
Read 2 more answers
Write the number 2 hundreds 15 tens 6 ones
AnnyKZ [126]
Hey the awnser is 20156 lol just kidding u Figueroa out lol ok
7 0
4 years ago
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Find the value of x.
alexgriva [62]

Answer:

x = 4\sqrt{2}

Step-by-step explanation:

note the exact value of tan60° = \sqrt{3}

Since the triangle is right use the tangent ratio to find x

tan60° = \frac{opposite}{adjacent} = \frac{4\sqrt{6} }{x}

multiply both sides by x

x × \sqrt{3} = 4\sqrt{6}

divide both sides by \sqrt{3}

x = \frac{4\sqrt{6} }{\sqrt{3} }= 4 × \sqrt{\frac{6}{3} } = 4\sqrt{2}


8 0
4 years ago
Read 2 more answers
What are the ordered pairs of the
Vlad1618 [11]

Answer:

{x}^{2}  - 2x + 3 =  - 6x \\  =  {x}^{2}  - 2x + 6x + 3 = 0 \\  \\  =  {x}^{2}  + 4x + 3 = 0 \\  = (x + 1)(x + 3) \\  = x =  - 1and \: x =  - 3

3 0
3 years ago
Find the value of x. Then find the measure of Arc AN. Show work on a piece of paper.
Arada [10]

Answer:

a. x = 36

b. ∠(AN) = 144°

Step-by-step explanation:

All the angle in the circle should add up to 360°.

x + x + 4x + 4x = 360

2x + 8x = 360

10x = 360

x = 36

∠(AN) = 4x

∠(AN) = 4(36)

∠(AN) = 144°

7 0
4 years ago
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