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OleMash [197]
2 years ago
5

I really need help on this it’s really urgent. Thank you :)

Mathematics
1 answer:
Flauer [41]2 years ago
6 0

Answer:

Step-by-step explanation:

-\frac{1}{3}y - \frac{1}{3} x

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Multiply both the numerator and denominator by 2+\sqrt3, which is called the "conjugate" of 2-\sqrt3:

\dfrac{5+\sqrt3}{2-\sqrt3}\cdot\dfrac{2+\sqrt3}{2+\sqrt3}

Why do we pick this number? Recall the difference of squares factorization:

a^2-b^2=(a-b)(a+b)

Now replace a=2 and b=\sqrt3. Then

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Finally, just expand the product.

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First, we are already given the sides adjacent and opposite to ∠x. Therefore, we can use the tangent function. Recall that:

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