The height h in feet of the ball t seconds after it is kicked can be modeled by the function h = -4t (4t - 11). How long is the football in the air?
1 answer:
Answer:
t₁ = 2,75 sec
Step-by-step explanation:
The ball will get h maximum when dh/dt ( its vertical component of the speed is equal to 0. At this moment the ball has flown half of the total flight time
Then
h(t) = - 4t * ( 4*t - 11 )
h(t) = - 16*t² + 44*t
Taking derivatives on both sides of the equation we get:
dh/dt = - 32*t + 44
dh/dt = 0 ⇒ -32*t + 44 = 0
t = 44/32 ⇒ t = 1,375 s
So twice this time
2*t = 2 * 1.375
Total time t₁ = 2,75 sec
You might be interested in
Angles, proportional sides, and scale factor
Answer:a,b,d,e,f.
Step-by-step explanation:hope it helps someone.
Answer:
Step-by-step explanation: cos. function theorem
a^2=b^2+c^2-2bc.cos(a)
Using the y=mx+b format, m the slope = (5--9)/(8--12) = 14/20 = 7/10=0.7 y-y1 = m(x-x1) y-5 = .7(x-8) = .7x-5.6 y = .7x +0.6 10y = 7x + 6 so 7x - 1y = -6 any your equation is almost correct.
Cut it once down the center horizontally, then make 4 equally spaced cuts virtically