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Fudgin [204]
3 years ago
9

HELP HELP HELP!! ILL MARK BRAINLIEST

Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
7 0

Answer: i think its the 3rd one

Step-by-step explanation:

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Choose the simplified form of the fifth term of the expansion. -60x2y8 -30x2y8 30x2y8 60x2y8
Vika [28.1K]

Answer:

Answer is D on edge

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
3 exponet 8×4+9÷1×56+57
nika2105 [10]
You would use PEMDAS

But since any number divided by 1 is the number by which it is divided by then you can eliminate that. Now your problem looks like this:
8✖️4➕9✖️56➕57

Since there are no parentheses or exponents then you would multiply.
8✖️4= 32
32➕9✖️56➕57

Then multiply the other multiplication problem.
9✖️56= 504
32➕504➕57

Now you can add all of the numbers together
32➕504=536
536➕57=593

Your answer is 593

Hope this helps! :3
4 0
3 years ago
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Which statement below best describes the transformation of parallelogram WXYZ to parallelogram W' X' Y' Z'?
Arisa [49]
The answer is B. A reflection across the x-axis.
6 0
3 years ago
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Hi, I am taking PSAT and I am working on the math section. I need help with answering this math type of question. Please give th
ValentinkaMS [17]

By using the concept of uniform rectilinear motion, the distance surplus of the average race car is equal to 3 / 4 miles. (Right choice: A)

<h3>How many more distance does the average race car travels than the average consumer car?</h3>

In accordance with the statement, both the average consumer car and the average race car travel at constant speed (v), in miles per hour. The distance traveled by the vehicle (s), in miles, is equal to the product of the speed and time (t), in hours. The distance surplus (s'), in miles, done by the average race car is determined by the following expression:

s' = (v' - v) · t

Where:

  • v' - Speed of the average race car, in miles per hour.
  • v - Speed of the average consumer car, in miles per hour.
  • t - Time, in hours.

Please notice that a hour equal 3600 seconds. If we know that v' = 210 mi / h, v = 120 mi / h and t = 30 / 3600 h, then the distance surplus of the average race car is:

s' = (210 - 120) · (30 / 3600)

s' = 3 / 4 mi

The distance surplus of the average race car is equal to 3 / 4 miles.

To learn more on uniform rectilinear motion: brainly.com/question/10153269

#SPJ1

4 0
1 year ago
The answer because it is hard
notka56 [123]
Follow me answer= -77
6 0
3 years ago
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