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3 years ago

11

Alexander builds a triangular frame with side lengths of 3 ft and 5 ft and a 120∘ angle between them. Which can be the length of

the unknown side of the frame?

1 answer:

antoniya [11.8K]3 years ago

4 0

Answer:

i got 7ft for the answer

Step-by-step explanation:

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For each equation below find y if x = 2

Charra [1.4K]

A.
y = 7 - |x| = 7 - 2 = 5

b.
y = x² - 1 = 2² - 1 = 4 - 1 = 3

c.
y = √(x + 14) = √(2 + 14) = √16 = 4

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3 years ago

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State whether the following is perpendicular or parallel y=(1/2)×y=-2×+9

Rom4ik [11]

Answer:

parallel!

Step-by-step explanation:

if you insert the equation into demos there parallel

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3 years ago

Water is leaking out of a large barrel at a rate proportional to the square rooot of the depth of the water at that time. If the

sdas [7]

Answer:

It will take about 35.49 hours for the water to leak out of the barrel.

Step-by-step explanation:

Let $y(t)$ be the depth of water in the barrel at time $t$ , where $y$ is measured in inches and $t$ in hours.

We know that water is leaking out of a large barrel at a rate proportional to the square root of the depth of the water at that time. We then have that

$\frac{dy}{dt}=-k\sqrt{y}$

where $k$ is a constant of proportionality.

Separation of variables is a common method for solving differential equations. To solve the above differential equation you must:

Multiply by $\frac{1}{\sqrt{y}}$

$\frac{1}{\sqrt{y}}\frac{dy}{dt}=-k$

Multiply by $dt$

$\frac{1}{\sqrt{y}}\cdot dy=-k\cdot dt$

Take integral

$\int \frac{1}{\sqrt{y}}\cdot dy=\int-k\cdot dt$

Integrate

$2\sqrt{y}=-kt+C$

Isolate $y$

$y(t)=(\frac{C}{2} -\frac{k}{2}t)^2$

We know that the water level starts at 36, this means $y(0)=36$ . We use this information to find the value of $C$ .

$36=(\frac{C}{2} -\frac{k}{2}(0))^2\\C=12$

$y(t)=(\frac{12}{2} -\frac{k}{2}t)^2\\\\y(t)=(6 -\frac{k}{2}t)^2$

At t = 1, y = 34

$34=(6 -\frac{k}{2}(1))^2\\k=12-2\sqrt{34}$

So our formula for the depth of water in the barrel is

$y(t)=(6 -\frac{12-2\sqrt{34}}{2}t)^2\\\\y(t)=\left(6-\left(6-\sqrt{34}\right)t\right)^2\\$

To find the time, $t$ , at which all the water leaks out of the barrel, we solve the equation

$\left(6-\left(6-\sqrt{34}\right)t\right)^2=0\\\\t=3\left(6+\sqrt{34}\right)\approx 35.49$

Thus, it will take about 35.49 hours for the water to leak out of the barrel.

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4 years ago

Kyndal wants to buy a lamp that

fenix001 [56]

Answer:

$39.36

Step-by-step explanation:

Since its 20% off that means we still have a remaining 80% so first multiply 0.8 to the 82

82x0.8= 65.6

Since there is a additional 40% off multiply by 0.4 to get the discount amount

65.6x0.4= 26.24

Subtract the discount from the price

65.6-26.24= 39.36

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3 years ago

6. Jeremy made a tally table to record

OlgaM077 [116]

Answer:

12

Step-by-step explanation:

add the tallys

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3 years ago

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