Answer:
36 36 32
Step-by-step explanation:
I think you're asking for a numerical answer, but you didn't mention
your score on the final.
Since the final is worth 10% (one tenth) of the grade, that 71 that you
have going into the final is worth 9/10 of the grade. So the way you
calculate your overall average is
Overall score = 1/10 of [ (71 x 9) + score on the final ] .
If you scored absolute zero on the final, your overall average would be
Overall score = (1/10) x [ (71 x 9) + 0 ] = (1/10) (639) = <u>63.9%</u> .
That's the lowest overall score for the class that you can have.
The <u>highest</u> overall score you could have would be if you got 100% on the final.
Then
Overall = (1/10) x (639 + 100) = (1/10) x (739) = <u>73.9%</u> .
If you got a 50% on the final, your overall would be
(1/10) x (639 + 50) = (1/10) x (689) = <u>68.9%</u> .
In general, your overall score for the class, after the final, is going to be
63.9% plus (1 tenth) of your score on the final.
Good luck !
Alright, so since the slope of the perpendicular line is -1/(slope), we get (-1/2)=-1/2 and y=(-1/2)x + something. Plugging 7 in as y and -4 in as x, we get 7=(-1/2)(4)+something (let's make it a variable b), and multiplying it out we get 7=-2+b. Adding 2 to both sides, we get 7+2=9=b, so the perpendicular line equation is therefore y=(-1/2)x+b<span />
Yes, as a line is a continuous object; it's infinite. A line segment is what you would use in a number line, per se.
