The value of xy from the given equation is (y ²z²)(√x÷ z²)
<h3>How to solve equation?</h3>
x = y ²z²
make y the subject
y² = x ÷ z²
y = √x÷ z²
xy = x × y
xy = (y ²z²)(√x÷ z²)
Therefore, the value of xy from the given equation is (y ²z²)(√x÷ z²)
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The confidence level and sample data to find a confidence interval for estimating the population mu. round your answer to the same number of decimal places as the sample mean 88.2 < μ < 93.0.
<h3>What are the confidence level?</h3>
The confidence stage refers to the proportion of probability, or certainty, that the self-belief c language could include the real populace parameter whilst you draw a random pattern many times.
- We have this given info:
- n = 92 = pattern length xbar = 90.6 = pattern imply
- sigma =8.! = populace popular deviation
- C=99% self-assurance level
- Because n > 30 and due to the fact we recognize sigma, this permits us to apply the Z distribution (aka popular ordinary distribution).
- At 99% self-assurance, the z essential price is more or less z = 2.576 use a reference sheet, table, or calculator to decide this.
- The decrease sure of the self assurance c programming language (L) is more or less L = xbar - z*sigma/sqrt(n) L = 90.6-2.576*8.9/sqrt(92) perp= 88.209757568781 perp= 88.2
- The top sure (U) of this self assurance c programming language is more or less U = xbar + z*sigma/sqrt(n) L = 88.209757568781 L = 88.2.
- The top sure (U) of this self assurance c programming language is more or less U=xbar+z^ * sigma/sqrt(n) U = 90.6 + 2.576*8.9/sqrt(92) U = 92.990242431219
- U = 93.0.
- Therefore, the self assurance c programming language withinside the format (L, U) is about (88.2, 93.zero).
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You would cube it so if theres a cube it answer than use that
Based on the Ksp calculations, the molar solubility of AgCl in 0.500 M of NH₃ is equal to 2.77 × 10⁻² M.
<h3>How to determine the molar solubility.</h3>
First of al, we would write the properly balanced chemical equation for this chemical reaction:
AgCl(s) ⇆ Ag⁺(aq)+ Cl⁻(aq) Ksp = 1.8 × 10⁻¹⁰
AgCl(s) + 2NH₃(aq) ⇆ Ag(NH₃)₂⁺(aq) Kf = 1. 7 × 10⁷
<u>Given the following data:</u>
- Ksp of AgCl = 1.8 × 10⁻¹⁰
- Concentration of NH₃ = 0.500
- Kf of ag(nh₃)₂⁺ = 1.7 × 10⁷
K = Ksp × Kf
K = 1. 80 × 10⁻¹⁰ × 1.7 × 10⁷
K = 3.06 × 10⁻³
Mathematically, the Ksp for the above chemical reaction is given by:
x = 2.77 × 10⁻² M.
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The statement about warming up before an activity that is not true is D. None of the above.
- Warming up is important as it helps in the prevention of injuries. It's also important as it helps blood flow into the muscles of a person and it's a great way to start a sweat.
- Warming up is also important for a person as it helps in preparing the body for aerobic activity. Warming up can also reduce the soreness of the muscle.
- Also, it is necessary to continue to stretch during the game as it helps in the prevention of injuries.
In conclusion, joints can also be warmed up through stretching.
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