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MakcuM [25]
3 years ago
15

Easy question -8 + (-9) = ?

Mathematics
2 answers:
Hatshy [7]3 years ago
8 0

Answer:

-17

Step-by-step explanation:

Darina [25.2K]3 years ago
4 0

Answer:

-17

Step-by-step explanation:

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PLEASE HELPPPPPPPPPP
Alexxx [7]

Answer:

Donna-71

Martina-62

Martina's sample

It has the smaller mean

Step-by-step explanation:

I apologize if this answer is incorrect but I think this is right.

6 0
3 years ago
a survey amony freshman at a certain university revealed that the number of hours spent studying the week before final exams was
Marat540 [252]

Answer:

Probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

Step-by-step explanation:

We are given that the number of hours spent studying the week before final exams was normally distributed with mean 25 and standard deviation 15.

A sample of 36 students was selected.

<em>Let </em>\bar X<em> = sample average time spent studying</em>

The z-score probability distribution for sample mean is given by;

          Z = \frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} }  ~ N(0,1)

where, \mu = population mean hours spent studying = 25 hours

            \sigma = standard deviation = 15 hours

            n = sample of students = 36

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the average time spent studying for the sample was between 29 and 30 hours studying is given by = P(29 hours < \bar X < 30 hours)

    P(29 hours < \bar X < 30 hours) = P(\bar X < 30 hours) - P(\bar X \leq 29 hours)

      

    P(\bar X < 30 hours) = P( \frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} } < \frac{ 30-25}{\frac{15}{\sqrt{36} } }} } ) = P(Z < 2) = 0.97725

    P(\bar X \leq 29 hours) = P( \frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} } \leq \frac{ 29-25}{\frac{15}{\sqrt{36} } }} } ) = P(Z \leq 1.60) = 0.94520

                                                                    

<em>So, in the z table the P(Z </em>\leq<em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 2 and x = 1.60 in the z table which has an area of 0.97725 and 0.94520 respectively.</em>

Therefore, P(29 hours < \bar X < 30 hours) = 0.97725 - 0.94520 = 0.0321

Hence, the probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

7 0
3 years ago
Vw=6 , uv=14 what is uw
vekshin1

Answer:

21

Step-by-step explanation:

if v=2

then uw=21

because 6/2=3, and

14/2=7

3x7=21

3 0
3 years ago
A plumber charges an initial fee of $60 and $15 per hour. Write an equation that represents how much the plumber charges, y, if
34kurt

Answer:

Y=15x+60

Step-by-step explanation:

6 0
2 years ago
Please help with areas
Softa [21]

Answer:

Step-by-step explanation:

7) The formula for determining the area of a parallelogram is expressed as

Area = base × height.

Length of base = Area/height

Therefore,

Length of base = 7/2 = 3.5 feet

8) The formula for determining the area of a trapezoid is expressed as

Area = 1/2(a + b)h

Where

a and b are the length of the bases

h is the height. Therefore

21 = 1/2(2 + 4)h

21 = 3h

h = 21/3 = 7 inches

9) Area = base × height.

Height = Area/Length of base

Height = 28/14 = 2 inches

10) a and b are 10 inches each.

Area = 1/2(a + b)h

Therefore,

35 = 1/2(10 + 10)h

35 = 10h

h = 35/10

h = 3 inches

7 0
3 years ago
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