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klemol [59]
3 years ago
11

Which proportion satisfies the geometric mean (altitude) theorem for the triangle?

Mathematics
2 answers:
Snezhnost [94]3 years ago
8 0

Answer:

D. \frac{2}{h}=\frac{h}{3}

Step-by-step explanation:

We have been given an image of a triangle. We are asked to choose the proportion that satisfies the geometric mean (altitude) theorem for the triangle.

The geometric mean (altitude) theorem states that altitude drawn from the right angle to hypotenuse divides the hypotenuse into two segments such that their product is equal to the altitude times altitude.

\frac{2}{h}=\frac{h}{3}

Therefore, option D is the correct choice.

Degger [83]3 years ago
3 0
D is the correct answer 
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3 years ago
Maury completed a bicycle race 1.5 hours faster than Vince at an average speed of 16 miles per hour. Vince completed the same ra
MAXImum [283]
Let the time taken by Vince to complete the race was x hours. 
Maury completed the race 1.5 hours faster. This means Maury complete the race in (x - 1.5) hours.

Average Speed of Maury = 16 miles per hour
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Distance = Speed x Time.

For Maury:
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For Vince:
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Since the distance covered by both was the same, we can equate the two equations as:

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3 years ago
How many solutions does 10+5x/15=4 have
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Step-by-step explanation:

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8 0
3 years ago
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Yoooooooooooooooooooooooooo can you please help me!?
klemol [59]
She has totally 10+5+3=18 marbles, so the probability is 10/18=5/9. The complement is (9-5)/9=4/9.

Hope this helped!
4 0
3 years ago
Unit rate for typing 34 words in a minute in a half
katrin [286]

Answer:

<u>R</u><u>a</u><u>t</u><u>e</u><u> </u><u>i</u><u>s</u><u> </u><u>1</u><u>.</u><u>1</u><u>3</u><u>3</u><u>3</u><u> </u><u>w</u><u>o</u><u>r</u><u>d</u><u>s</u><u> </u><u>p</u><u>e</u><u>r</u><u> </u><u>s</u><u>e</u><u>c</u><u>o</u><u>n</u><u>d</u><u> </u>

Step-by-step explanation:

We understand rating as frequency or speed of doing something per time (seconds mainly)

{ \green{ \tt{rate = \frac{item \: quantity}{time}  }}} \\

Let's find rate in terms of seconds (words per second)

{ \rm{rate =  \frac{34 \: words}{ (\frac{1}{2} \times 60)  \: seconds} }} \\  \\ { \rm{rate =  \frac{34}{30} }} \\  \\ { \rm{rate = 1.133 \:  \: words \: per \: second}}

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