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Lana71 [14]
3 years ago
9

The width of a rectangle is 8y- 1.5 feet and the length is 1.5y+9 feet. Find the perimeter of the rectangle.

Mathematics
1 answer:
lyudmila [28]3 years ago
6 0

Answer:

P=19y+15

Step-by-step explanation:

Step one:

Given data

dimension of the rectangle

Width = 8y-1.5

Length = 1.5y+9

Required

The expression to represents the Perimeter

Step two:

the perimeter of  a rectangle is expressed as

P= 2L+2W\\\\P=2(1.5y+9)+2(8y-1.5)\\\\P=3y+18+16y-3\\\\

collect like terms

P=3y+16y+18-3\\\\P=19y+15

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(Brainliest for fastest right answer!!) Which is correct?
Arisa [49]

Answer:

<em>(n - 5)(n + 5) </em>

Step-by-step explanation:

a² - b² = (a - b)(a + b)

n² - 25 = n² - 5² = <em>(n - 5)(n + 5)</em>

7 0
2 years ago
What is the answer please help
matrenka [14]

Answer:

7

Step-by-step explanation:

7 shows up twice

all other numbers show up only once.

6 0
3 years ago
How do I simplify this?
Fudgin [204]
This is the theory of algebra, to simply the expression we proceed as follows;
[sqrt(x-2)+5/sqrt(x-2)]/(x-2)
simplifying the numerator we get:
sqrt(x-2)+5/sqrt(x-2)
=[x-2+5]/sqrt(x-2)
=(x+3)/sqrt(x-2)
therefore our entire expression will be:
[(x+3)/sqrt(x-2)]/(x-2)
[(x+3)/(x-2)^(1/2)]*1/(x-2)
applying the law if indices we get
=(x+3)/(x-2)^(3/2)
7 0
3 years ago
What is the slope-intercept form of the equation of a line that passes through (5, -4) and has a slope of 34?
Alla [95]
One way to find the slope-intercept form is to plug the given values into point-slope form, y - y_{1} = m (x - x_{1}), where x_{1} and y_{1} are the coordinate points and m is the slope. Then, you solve for y.

y - y_{1} = m (x - x_{1})   Plug in the values
  y - (-4) = 34 (x - 5)         Fix the minus negative four
     y + 4 = 34 (x - 5)         Use the Distributive Property
     y + 4 = 34x - 170        Subtract 4 from both sides
           y = 34x - 174

The slope-intercept form of the equation that passes through (5, -4) and has a slope of 34 is y = 34x - 174.

6 0
2 years ago
PLZ HELP NNOOOOOOOWW!! 15 points!!
motikmotik
The midpoint of the line having the endpoints (x_1,y_1) and (x_2,y_2) is (\frac{x_{1}+_x_{2}}{2}, \frac{y_{1}+_y_{2}}{2})
basically average them


so given that the line has the endpoints of (-3,7) and (9,-2)
x₁=-3
y₁=7
x₂=9
y₂=-2

so the midpoint can be found by doing
(\frac{-3+9}{2}, \frac{7+(-2)}{2})=
(\frac{6}{2}, \frac{7-2}{2})=
(3, \frac{5}{2})

the midpoint is (3,\frac{5}{2})
4 0
2 years ago
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