Answer:
a) 95% of the widget weights lie between 29 and 57 ounces.
b) What percentage of the widget weights lie between 12 and 57 ounces? about 97.5%
c) What percentage of the widget weights lie above 30? about 97.5%
Step-by-step explanation:
The empirical rule for a mean of 43 and a standard deviation of 7 is shown below.
a) 29 represents two standard deviations below the mean, and 57 represents two standard deviations above the mean, so, 95% of the widget weights lie between 29 and 57 ounces.
b) 22 represents three standard deviations below the mean, and the percentage of the widget weights below 22 is only 0.15%. We can say that the percentage of widget weights below 12 is about 0. Equivalently we can say that the percentage of widget weights between 12 an 43 is about 50% and the percentage of widget weights between 43 and 57 is 47.5%. Therefore, the percentage of the widget weights that lie between 12 and 57 ounces is about 97.5%
c) The percentage of widget weights that lie above 29 is 47.5% + 50% = 97.5%. We can consider that the percentage of the widget weights that lie above 30 is about 97.5%
Answer:
No Solutions
X=2
Infinite Solutions
No Solutions
X=0
X=-3
Infinite Solutions
Step-by-step explanation:
Sorry if any of them are wrong.
Answer:
6:10 -> simplfied is 3:5
Step-by-step explanation:
This question is really is if you think about it for a while. If you have a ratio that is like 6:10 or 6/10 all you have to do is multiply it by two (since it can only go in two times in this ratio). When you simplfy your answer, you will get 3:5.
Hope this helped you guys!
0.92085175 radians
Let's first calculate the length of the diagonal of the base. Using the Pythagorean theorem:
b = sqrt(9^2 + 7^2) = sqrt(81 + 49) = sqrt(130) = 11.40175425
Now the length of the diagonal to the box. Once again, using the Pythagorean theorem:
d = sqrt(15^2 + 11.40175425^2) = sqrt(225 + 130) = sqrt(335) = 18.84144368
We now have a right triangle where we know the lengths of all three sides. The lengths are:
a = 15
b = sqrt(130) ≠11.40175425
c = sqrt(335) ≠18.84144368
we want the angle opposite to side a. So
tan(A) = 15/11.40175425 = 1.315587029
A = atan(1.315587029)
A = 0.92085175 radians
Answer:
A meter is 1000 times the length of a kilometer.
